oracle_去掉重复记录

比如现在有一人员表 (表名:peosons

若想将姓名、身份证号、住址这三个字段完全相同的记录查询出来

select p1.*  

from persons  p1,persons  p2  

where p1.id<>p2.id  

and  p1.cardid = p2.cardid and p1.pname = p2.pname and p1.address = p2.address

 

 

可以实现上述效果.

 

几个删除重复记录的SQL语句

 

1.rowid方法

 

2.group by方法

 

3.distinct方法

 

1。用rowid方法

 

据据oracle带的rowid属性,进行判断,是否存在重复,语句如下:

 

查数据:

 

     select * from table1 a where rowid !=(select max(rowid)

     from table1 b where a.name1=b.name1 and a.name2=b.name2......)

 

删数据:

 

    delete  from table1 a where rowid !=(select max(rowid)

    from table1 b where a.name1=b.name1 and a.name2=b.name2......)

 

2.group by方法

 

查数据:

 

  select count(num), max(name) from student --列出重复的记录数,并列出他的name属性

  group by num

  having count(num) >1 --num分组后找出表中num列重复,即出现次数大于一次

 

删数据:

 

  delete from student

  group by num

  having count(num) >1

  这样的话就把所有重复的都删除了。

 

3.distinct方法 -对于小的表比较有用

 

 

create table table_new as   select distinct *   from table1 minux

truncate table table1;

insert into table1 select * from table_new;

 

查询及删除重复记录的方法大全

 

1、查找表中多余的重复记录,重复记录是根据单个字段(peopleId)来判断

select * from people

where peopleId in (select peopleId from people group by peopleId having count(peopleId) > 1)

 

 

2、删除表中多余的重复记录,重复记录是根据单个字段(peopleId)来判断,只留有rowid最小的记录

delete from people

where peopleId in (select peopleId from people group by peopleId  

having count(peopleId) > 1)

and rowid not in (select min(rowid) from people group by peopleId having count(peopleId )>1)

 

 

3、查找表中多余的重复记录(多个字段)

select * from vitae a

where (a.peopleId,a.seq) in (select peopleId,seq from vitae group by peopleId,seq having count(*) > 1)

 

 

4、删除表中多余的重复记录(多个字段),只留有rowid最小的记录

delete from vitae a

where (a.peopleId,a.seq) in (select peopleId,seq from vitae group by peopleId,seq having count(*) > 1)

and rowid not in (select min(rowid) from vitae group by peopleId,seq having count(*)>1)

 

 

5、查找表中多余的重复记录(多个字段),不包含rowid最小的记录

select * from vitae a

where (a.peopleId,a.seq) in (select peopleId,seq from vitae group by peopleId,seq having count(*) > 1)

and rowid not in (select min(rowid) from vitae group by peopleId,seq having count(*)>1)

 

 

()

比方说

A表中存在一个字段“name”,

而且不同记录之间的“name”值有可能会相同,

现在就是需要查询出在该表中的各记录之间,“name”值存在重复的项;

Select Name,Count(*) From A Group By Name Having Count(*) > 1

如果还查性别也相同大则如下:

Select Name,sex,Count(*) From A Group By Name,sex Having Count(*) > 1

 

()

方法一

declare @max integer,@id integer

declare cur_rows cursor local for select 主字段,count(*) from 表名 group by 主字段 having count(*) > 1

open cur_rows

fetch cur_rows into @id,@max

while @@fetch_status=0

begin

select @max = @max -1

set rowcount @max

delete from 表名 where 主字段 = @id

fetch cur_rows into @id,@max

end

close cur_rows

set rowcount 0

 

 

方法二

"重复记录"有两个意义上的重复记录,一是完全重复的记录,也即所有字段均重复的记录,二是部分关键字段重复的记录,

比如Name字段重复,而其他字段不一定重复或都重复可以忽略。

 

1、对于第一种重复,比较容易解决,使用

select distinct * from tableName就可以得到无重复记录的结果集。

如果该表需要删除重复的记录(重复记录保留1条),可以按以下方法删除

select distinct * into #Tmp from tableName

drop table tableName

select * into tableName from #Tmp

drop table #Tmp

发生这种重复的原因是表设计不周产生的,增加唯一索引列即可解决。

 

 

2、这类重复问题通常要求保留重复记录中的第一条记录,操作方法如下

假设有重复的字段为Name,Address,要求得到这两个字段唯一的结果集

select identity(int,1,1) as autoID, * into #Tmp from tableName

select min(autoID) as autoID into #Tmp2 from #Tmp group by Name,autoID

select * from #Tmp where autoID in(select autoID from #tmp2)

  最后一个select即得到了NameAddress不重复的结果集(但多了一个autoID字段,实际写时可以写在select子句中省去此列)

 

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查询重复

select * from tablename where id in (

select id from tablename

group by id

having count(id) > 1

)

 

 

 

例子

delete from w_m_mjout where ksid in

(select ksid from tableName group by ksid HAVING COUNT(ksid)>1)

and rowid not in (select min(ROWID) from tableName group by ksid HAVING COUNT(ksid)>1)

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转载自lichunhui.iteye.com/blog/1702419