16进制的IEEE 754格式转十进制

import struct
# s = 'F4CEF042' # 42C80000


# s = "0000B442"
s = "0000C842"

print(s)
#<是小端,>是大端,f代表浮点数
print(struct.unpack('<f', bytes.fromhex(s))[0])#小端
# print(struct.unpack('<f', bytes.fromhex(s)))#小端
#输出:120.40420532226562
s = float('6.55563714424545E-10')
print(struct.pack('<f', s).hex())#小端
#输出:32333430
print(struct.pack('>f', s).hex())#大端
#输出:30343332

import binascii
import struct
speed_string2 = "000009D8"
b = binascii.a2b_hex(speed_string2.encode())
speed_val = struct.unpack('i', b)[0]

猜你喜欢

转载自blog.csdn.net/weixin_43134049/article/details/120804619
今日推荐