PHP 命令行模式下获取参数的方法

命令行模式下获取参数的方法

命令行模式下，$_SERVER[‘argv’] 的值为数组。

例如：D:\wamp\bin\php\php5.3.13>php D:\wamp\www\test\argv.php a1=123 ee=‘q1’ 123

var_dump($_SERVER['argv'])显示如下：

array(4) {
    
    
  [0] =>
  string(25) "D:\\wamp\\www\\test\\argv.php"
  [1] =>
  string(8) "a1=123"
  [2] =>
  string(5) "ee='q1'"
  [3] =>
  string(3) "123"
}

//获取参数：

$arArg = array();


foreach ($_SERVER['argv'] as $arg ){
    
    
 if ( strpos($arg, '=') ) {
    
    
  list($key, $val) = explode('=', $arg);
  $arArg[$key] = $val;
 }
}

var_dump($arArg);

Web下，此值为null。

测试

<?php

var_export($_SERVER['argv']);

D:\application\admin_ahlan_simple>php test.php m=aaaatest a=test
array (
  0 => 'test.php',
  1 => 'm=aaaatest',
  2 => 'a=test',
)
D:\application\admin_ahlan_simple>php test.php m=aaaatest/a=test
array (
  0 => 'test.php',
  1 => 'm=aaaatest/a=test',
)
D:\application\admin_ahlan_simple>php test.php /user/get
array (
  0 => 'test.php',
  1 => '/user/get',
)

转载于:https://www.cnblogs.com/shanheshui/p/4486723.html