--注意HAVING里不支持别名 SELECT k001,k002,k003,k004,k005,COUNT(DISTINCT k006) cc FROM asis.gbno WHERE k005 = '3' GROUP BY k001,k002,k003,k004,k005 HAVING COUNT( DISTINCT k006) > 1
Oracle having
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转载自southking.iteye.com/blog/1727978
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