mysql | 计算排名

> 计算排名

例子:
https://www.1keydata.com/tw/sql/sql-rank.html

给出每个人的排名

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SELECT a1.Name, a1.Sales, COUNT(a2.Sales) Sales_Rank 
FROM Total_Sales a1, Total_Sales a2 
WHERE a1.Sales <= a2.Sales OR (a1.Sales=a2.Sales AND a1.Name = a2.Name) 
GROUP BY a1.Name, a1.Sales 
ORDER BY a1.Sales DESC, a1.Name DESC;

LeetCode上的计算排名:

https://leetcode.com/problems/rank-scores/description/
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结果:
这里写图片描述

方案一:

SELECT
  Score,
  @rank := @rank + (@prev <> (@prev := Score)) Rank
FROM
  Scores,
  (SELECT @rank := 0, @prev := -1) init
ORDER BY Score desc

方案二:

SELECT
  Score,
  (SELECT count(distinct Score) FROM Scores WHERE Score >= s.Score) Rank
FROM Scores s
ORDER BY Score desc

方案三:

SELECT
  Score,
  (SELECT count(*) FROM (SELECT distinct Score s FROM Scores) tmp WHERE s >= Score) Rank
FROM Scores
ORDER BY Score desc

方案四:

SELECT s.Score, count(distinct t.score) Rank
FROM Scores s JOIN Scores t ON s.Score <= t.score
GROUP BY s.Id
ORDER BY s.Score desc

总结出来,以供自己学习之用。

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转载自blog.csdn.net/xxzhangx/article/details/78170019