有无虚函数的继承

用这个方法A.什么的调用的都是自己
弗父类的指针可以指向儿子，儿子的指针不能调用老爸
如果不是虚函数
老爸的指针只能调用自己
如果有虚函数
老爸的指针指向谁就调用谁

#include <iostream>
using namespace std;

class A 
{
    
    
	private:
		int x;
		int y;
	public:
		A(int i, int j) 
		{
    
    
			x = i;
			y = j;
		}
		virtual void disp() 
		{
    
    
			cout << "x=" << x << " " << "y=" << y << endl;
		}
};

class B: public A 
{
    
    
		int z;
	public:
		B(int i, int j, int k): A(i, j) 
		{
    
    
			z = k;
		}
		virtual void disp() 
		{
    
    
			cout << "z=" << z << endl;
		}
};

int main () 
{
    
    
	A a(50, 100), *p;
	B b(1, 2, 3);
	a.disp();
	cout << endl;
	b.disp();
	cout << endl;
	p = &a;
	p->disp();
	cout << endl;
	p = &b;
	p->disp();
	return 0;
}

#include <iostream>
using namespace std;

class A 
{
    
    
	private:
		int x;
		int y;
	public:
		A(int i, int j) 
		{
    
    
			x = i;
			y = j;
		}
		void disp() 
		{
    
    
			cout << "x=" << x << " " << "y=" << y << endl;
		}
};

class B: public A 
{
    
    
		int z;
	public:
		B(int i, int j, int k): A(i, j) 
		
		{
    
    
			z = k;
		}
		void disp() 
		{
    
    
			cout << "z=" << z << endl;
		}
};
int main () 
{
    
    
	A a(50, 100), *p;
	B b(1, 2, 3);
	a.disp();
	cout << endl;
	b.disp();
	cout << endl;
	p = &a;
	p->disp();
	cout << endl;
	p = &b;
	p->disp();
	return 0;
}