洛谷 P1957 口算练习题 题解 字符串 C/C++

//P1957 口算练习题
#define LOCAL
#include <iostream>
#include <cstdio>
#include <cstring>
#include <cmath>
#include <algorithm>
#include <cctype>
#define inf 0x3f3f3f3f
#define eps 1e-6
using namespace std;
#define clr(x) memset(x,0,sizeof((x)))
const int maxn = 5e4+1;//2e6+1
#define MAX(a,b,c) ((a)>(b)?((a)>(c)?(a):(c)):((b)>(c)?(b):(c)))
#define _max(a,b) ((a) > (b) ? (a) : (b))
#define _min(a,b) ((a) < (b) ? (a) : (b))
#define _for(a,b,c) for(int a = b;a<c;a++)

int main() {
    
    
#ifdef LOCAL 
	freopen("data.in","r",stdin);
	freopen("data.out","w",stdout);
#endif
	int n,op1,op2;
	cin>>n;
	char s[100],ch;
	for(int i = 0;i<n;i++) {
    
    
		scanf("%s",s);
		if(s[0]>='a'&&s[0]<='c') {
    
    
			ch = s[0];
			scanf("%d%d",&op1,&op2);
		}
		else {
    
    
			sscanf(s,"%d",&op1);//输入到op1
			scanf("%d",&op2);
		}
		clr(s);
		switch(ch) {
    
    
			case 'a':sprintf(s,"%d+%d=%d",op1,op2,op1+op2);break;//输出到s;
			case 'b':sprintf(s,"%d-%d=%d",op1,op2,op1-op2);break;
			case 'c':sprintf(s,"%d*%d=%d",op1,op2,op1*op2);break;
		}
		int len = strlen(s);
		for(int i = 0;i<len;i++) {
    
    
			printf("%c",s[i]);
		}
		printf("\n%d\n",len);
	}
	return 0;
}