select * from mytest where (select DATEDIFF(now(),current)=0) ;//今天的数据
SELECT OrderId,DATE_ADD(OrderDate,INTERVAL 2 DAY)
AS OrderPayDate FROM Orders 向 "OrderDate" 添加 2 天 即结果为 2008-12-31 16:25:46.635 SELECT OrderId,DATE_SUB(OrderDate,INTERVAL 2 DAY)
AS OrderPayDate FROM Orders 从 "OrderDate" 减去 2 天 结果:2008-12-27 16:25:46.635 DATEDIFF() 函数返回两个日期之间的天数。 date1 和 date2 参数是合法的日期或日期/时间表达式。 注释:只有值的日期部分参与计算。 SELECT DATEDIFF('2008-12-30','2008-12-29') AS DiffDate 结果1 SELECT DATEDIFF('2008-12-29','2008-12-30') AS DiffDate 结果-1