分别使用for()、while()和do while()循环实现n(1≤n≤100)个数的累加求和

#include<stdio.h>
int f1(short n)//使用while()循环
{
    int Sum=0;
    int m;
    short i=1;
    while(i<=n)
    {
        scanf("%d", &m);
        Sum=Sum+m;
        i++;
    }
    return Sum;
}
int f2(short n)//使用for()循环
{
    int Sum=0;
    int m;
    short i;
    for(i=1;i<=n;i++)
    {
        scanf("%d", &m);
        Sum=Sum+m;
    }
    return Sum;
}
int f3(short n)//使用do while()循环
{
    int Sum=0;
    int m;
    short i=1;
    do{
        scanf("%d", &m);
        Sum=Sum+m;
        i++;
    }
    while(i<=n);
    return Sum;
}
int main()
{
    short n;
    printf("1+2+...+n: \n");
    printf("Please input n: ");
    scanf("%hd", &n);
    if(n>=1&&n<=100)
    {
        printf("Sum=%d\n", f1(n));
        printf("Sum=%d\n", f2(n));
        printf("Sum=%d\n", f3(n));
    }
    else//n值不合法
    {
        printf("error!\n");
    }
    return 0;
}

 

 

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转载自blog.csdn.net/weixin_42048463/article/details/115111994