CompletableFuture API2
thenCombine 合并任务
thenCombine 会把 两个 CompletionStage 的任务都执行完成后，把两个任务的结果一块交给 thenCombine 来处理。
public <U,V> CompletionStage<V> thenCombine(CompletionStage<? extends U> other,BiFunction<? super T,? super U,? extends V> fn);
public <U,V> CompletionStage<V> thenCombineAsync(CompletionStage<? extends U> other,BiFunction<? super T,? super U,? extends V> fn);
public <U,V> CompletionStage<V> thenCombineAsync(CompletionStage<? extends U> other,BiFunction<? super T,? super U,? extends V> fn,Executor executor);
示例
private static void thenCombine() throws Exception {
CompletableFuture<String> future1 = CompletableFuture.supplyAsync(new Supplier<String>() {
@Override
public String get() {
return "hello";
}
});
CompletableFuture<String> future2 = CompletableFuture.supplyAsync(new Supplier<String>() {
@Override
public String get() {
return "hello";
}
});
CompletableFuture<String> result = future1.thenCombine(future2, new BiFunction<String, String, String>() {
@Override
public String apply(String t, String u) {
return t+" "+u;
}
});
System.out.println(result.get());
}
thenAcceptBoth
当两个CompletionStage都执行完成后，把结果一块交给thenAcceptBoth来进行消耗
public <U> CompletionStage<Void> thenAcceptBoth(CompletionStage<? extends U> other,BiConsumer<? super T, ? super U> action);
public <U> CompletionStage<Void> thenAcceptBothAsync(CompletionStage<? extends U> other,BiConsumer<? super T, ? super U> action);
public <U> CompletionStage<Void> thenAcceptBothAsync(CompletionStage<? extends U> other,BiConsumer<? super T, ? super U> action, Executor executor);
示例
private static void thenAcceptBoth() throws Exception {
CompletableFuture<Integer> f1 = CompletableFuture.supplyAsync(new Supplier<Integer>() {
@Override
public Integer get() {
int t = new Random().nextInt(3);
try {
TimeUnit.SECONDS.sleep(t);
} catch (InterruptedException e) {
e.printStackTrace();
}
System.out.println("f1="+t);
return t;
}
});
CompletableFuture<Integer> f2 = CompletableFuture.supplyAsync(new Supplier<Integer>() {
@Override
public Integer get() {
int t = new Random().nextInt(3);
try {
TimeUnit.SECONDS.sleep(t);
} catch (InterruptedException e) {
e.printStackTrace();
}
System.out.println("f2="+t);
return t;
}
});
f1.thenAcceptBoth(f2, new BiConsumer<Integer, Integer>() {
@Override
public void accept(Integer t, Integer u) {
System.out.println("f1="+t+";f2="+u+";");
}
});
}
applyToEither 方法
两个CompletionStage，谁执行返回的结果快，我就用那个CompletionStage的结果进行下一步的转化操作。
public <U> CompletionStage<U> applyToEither(CompletionStage<? extends T> other,Function<? super T, U> fn);
public <U> CompletionStage<U> applyToEitherAsync(CompletionStage<? extends T> other,Function<? super T, U> fn);
public <U> CompletionStage<U> applyToEitherAsync(CompletionStage<? extends T> other,Function<? super T, U> fn,Executor executor);
示例
private static void applyToEither() throws Exception {
CompletableFuture<Integer> f1 = CompletableFuture.supplyAsync(new Supplier<Integer>() {
@Override
public Integer get() {
int t = new Random().nextInt(3);
try {
TimeUnit.SECONDS.sleep(t);
} catch (InterruptedException e) {
e.printStackTrace();
}
System.out.println("f1="+t);
return t;
}
});
CompletableFuture<Integer> f2 = CompletableFuture.supplyAsync(new Supplier<Integer>() {
@Override
public Integer get() {
int t = new Random().nextInt(3);
try {
TimeUnit.SECONDS.sleep(t);
} catch (InterruptedException e) {
e.printStackTrace();
}
System.out.println("f2="+t);
return t;
}
});
CompletableFuture<Integer> result = f1.applyToEither(f2, new Function<Integer, Integer>() {
@Override
public Integer apply(Integer t) {
System.out.println(t);
return t * 2;
}
});
System.out.println(result.get());
}
acceptEither 方法
两个CompletionStage，谁执行返回的结果快，我就用那个CompletionStage的结果进行下一步的消耗操作。
public CompletionStage<Void> acceptEither(CompletionStage<? extends T> other,Consumer<? super T> action);
public CompletionStage<Void> acceptEitherAsync(CompletionStage<? extends T> other,Consumer<? super T> action);
public CompletionStage<Void> acceptEitherAsync(CompletionStage<? extends T> other,Consumer<? super T> action,Executor executor);
示例
private static void acceptEither() throws Exception {
CompletableFuture<Integer> f1 = CompletableFuture.supplyAsync(new Supplier<Integer>() {
@Override
public Integer get() {
int t = new Random().nextInt(3);
try {
TimeUnit.SECONDS.sleep(t);
} catch (InterruptedException e) {
e.printStackTrace();
}
System.out.println("f1="+t);
return t;
}
});
CompletableFuture<Integer> f2 = CompletableFuture.supplyAsync(new Supplier<Integer>() {
@Override
public Integer get() {
int t = new Random().nextInt(3);
try {
TimeUnit.SECONDS.sleep(t);
} catch (InterruptedException e) {
e.printStackTrace();
}
System.out.println("f2="+t);
return t;
}
});
f1.acceptEither(f2, new Consumer<Integer>() {
@Override
public void accept(Integer t) {
System.out.println(t);
}
});
}
runAfterEither 方法
两个CompletionStage，任何一个完成了都会执行下一步的操作（Runnable）
public CompletionStage<Void> runAfterEither(CompletionStage<?> other,Runnable action);
public CompletionStage<Void> runAfterEitherAsync(CompletionStage<?> other,Runnable action);
public CompletionStage<Void> runAfterEitherAsync(CompletionStage<?> other,Runnable action,Executor executor);
示例
private static void runAfterEither() throws Exception {
CompletableFuture<Integer> f1 = CompletableFuture.supplyAsync(new Supplier<Integer>() {
@Override
public Integer get() {
int t = new Random().nextInt(3);
try {
TimeUnit.SECONDS.sleep(t);
} catch (InterruptedException e) {
e.printStackTrace();
}
System.out.println("f1="+t);
return t;
}
});
CompletableFuture<Integer> f2 = CompletableFuture.supplyAsync(new Supplier<Integer>() {
@Override
public Integer get() {
int t = new Random().nextInt(3);
try {
TimeUnit.SECONDS.sleep(t);
} catch (InterruptedException e) {
e.printStackTrace();
}
System.out.println("f2="+t);
return t;
}
});
f1.runAfterEither(f2, new Runnable() {
@Override
public void run() {
System.out.println("上面有一个已经完成了。");
}
});
}
runAfterBoth
两个CompletionStage，都完成了计算才会执行下一步的操作（Runnable）
public CompletionStage<Void> runAfterBoth(CompletionStage<?> other,Runnable action);
public CompletionStage<Void> runAfterBothAsync(CompletionStage<?> other,Runnable action);
public CompletionStage<Void> runAfterBothAsync(CompletionStage<?> other,Runnable action,Executor executor);
示例
private static void runAfterBoth() throws Exception {
CompletableFuture<Integer> f1 = CompletableFuture.supplyAsync(new Supplier<Integer>() {
@Override
public Integer get() {
int t = new Random().nextInt(3);
try {
TimeUnit.SECONDS.sleep(t);
} catch (InterruptedException e) {
e.printStackTrace();
}
System.out.println("f1="+t);
return t;
}
});
CompletableFuture<Integer> f2 = CompletableFuture.supplyAsync(new Supplier<Integer>() {
@Override
public Integer get() {
int t = new Random().nextInt(3);
try {
TimeUnit.SECONDS.sleep(t);
} catch (InterruptedException e) {
e.printStackTrace();
}
System.out.println("f2="+t);
return t;
}
});
f1.runAfterBoth(f2, new Runnable() {
@Override
public void run() {
System.out.println("上面两个任务都执行完成了。");
}
});
}
thenCompose 方法
thenCompose 方法允许你对两个 CompletionStage 进行流水线操作，第一个操作完成时，将其结果作为参数传递给第二个操作。
public <U> CompletableFuture<U> thenCompose(Function<? super T, ? extends CompletionStage<U>> fn);
public <U> CompletableFuture<U> thenComposeAsync(Function<? super T, ? extends CompletionStage<U>> fn) ;
public <U> CompletableFuture<U> thenComposeAsync(Function<? super T, ? extends CompletionStage<U>> fn, Executor executor) ;
示例
private static void thenCompose() throws Exception {
CompletableFuture<Integer> f = CompletableFuture.supplyAsync(new Supplier<Integer>() {
@Override
public Integer get() {
int t = new Random().nextInt(3);
System.out.println("t1="+t);
return t;
}
}).thenCompose(new Function<Integer, CompletionStage<Integer>>() {
@Override
public CompletionStage<Integer> apply(Integer param) {
return CompletableFuture.supplyAsync(new Supplier<Integer>() {
@Override
public Integer get() {
int t = param *2;
System.out.println("t2="+t);
return t;
}
});
}
});
System.out.println("thenCompose result : "+f.get());
}