描述
Given two integer arrays startTime and endTime and given an integer queryTime.
The ith student started doing their homework at the time startTime[i] and finished it at time endTime[i].
Return the number of students doing their homework at time queryTime. More formally, return the number of students where queryTime lays in the interval [startTime[i], endTime[i]] inclusive.
Example 1:
Input: startTime = [1,2,3], endTime = [3,2,7], queryTime = 4
Output: 1
Explanation: We have 3 students where:
The first student started doing homework at time 1 and finished at time 3 and wasn't doing anything at time 4.
The second student started doing homework at time 2 and finished at time 2 and also wasn't doing anything at time 4.
The third student started doing homework at time 3 and finished at time 7 and was the only student doing homework at time 4.
Example 2:
Input: startTime = [4], endTime = [4], queryTime = 4
Output: 1
Explanation: The only student was doing their homework at the queryTime.
Example 3:
Input: startTime = [4], endTime = [4], queryTime = 5
Output: 0
Example 4:
Input: startTime = [1,1,1,1], endTime = [1,3,2,4], queryTime = 7
Output: 0
Example 5:
Input: startTime = [9,8,7,6,5,4,3,2,1], endTime = [10,10,10,10,10,10,10,10,10], queryTime = 5
Output: 5
Note:
startTime.length == endTime.length
1 <= startTime.length <= 100
1 <= startTime[i] <= endTime[i] <= 1000
1 <= queryTime <= 1000
解析
解答
class Solution(object):
def busyStudent(self, startTime, endTime, queryTime):
"""
:type startTime: List[int]
:type endTime: List[int]
:type queryTime: int
:rtype: int
"""
num = 0
for i in range(len(startTime)):
if startTime[i]<= queryTime and queryTime<=endTime[i]:
num += 1
return num
运行结果
Runtime: 24 ms, faster than 74.42% of Python online submissions for Number of Students Doing Homework at a Given Time.
Memory Usage: 13.1 MB, less than 99.46% of Python online submissions for Number of Students Doing Homework at a Given Time.
原题链接：https://leetcode.com/problems/number-of-students-doing-homework-at-a-given-time/