把字符串里的整数倒叙一个一个打印出来

把字符串里的整数倒叙一个一个打印出来

int count = 0;
void myRevert(int n, int a[])
{
	if (n < 10)
	{
		a[count++] = n;
	}
	else
	{
		a[count++] = n % 10;
		myRevert(n / 10, a);
	}
}

int main()
{
	int n;
	int b[7];
	const char *a = "123456";
    n = atoi(a);
	myRevert(n, b);
	for (int j = 0; j < count; j++)
	{
		printf("%d\n", b[j]);
	}

	getchar();
	return 0;
}