javaweb之servlet-------01

1.创建maven项目

2.添加servlet依赖

<dependencies>
        <dependency>
            <groupId>javax.servlet</groupId>
            <artifactId>javax.servlet-api</artifactId>
            <version>4.0.1</version>
        </dependency>
    </dependencies>

3.更换webapp下的web.xml

<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns="http://xmlns.jcp.org/xml/ns/javaee"
         xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
         xsi:schemaLocation="http://xmlns.jcp.org/xml/ns/javaee http://xmlns.jcp.org/xml/ns/javaee/web-app_4_0.xsd"
         version="4.0"
         metadata-complete="true">
</web-app>

4.在java包下编写servlet类

//继承HttpServlet ,重写doGet和doPost方法
public class HelloServlet extends HttpServlet {
    
    

    @Override
    protected void doGet(HttpServletRequest req, HttpServletResponse resp) throws ServletException, IOException {
    
    

        System.out.println("进入了doget方法");
//        resp.getOutputStream();

        PrintWriter writer = resp.getWriter();

        writer.println("Hello World!");

    }
}

5.配置servlet在web.xml

<servlet>
    <servlet-name>hello</servlet-name>
    <servlet-class>top.chenyp.servlet.HelloServlet</servlet-class>
    </servlet>
    
    <servlet-mapping>
        <servlet-name>hello</servlet-name>
        <url-pattern>/hello</url-pattern>
    </servlet-mapping>

6.配置tomcat

7.运行

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转载自blog.csdn.net/qq_42794826/article/details/113809103