java中lableB跳出循环
lableB:
break lableB;
import java.util.Scanner;
public class test {
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
//输入数字数组
String str = scanner.next().toString();
//输出目标值
int aim = scanner.nextInt();
//数组输入分割符用逗号隔开
String[] arr = str.split(",");
//创建一个数组
int[] b = new int[arr.length];
//循环输出
for(int j = 0; j<b.length;j++) {
b[j] = Integer.parseInt(arr[j]);
}
int c=0;
lableB:
for(int i = 0; i<b.length; i++){
lableA:
for(int j=i+1;j<b.length;j++) {
c = b[i] + b[j];
if (aim == c) {
System.out.print(i);
System.out.print(",");
System.out.print(j);
break lableB;
}
}
}
}
}