opencv——图像中的四则运算（图像混合）

原理

图像混合实际上是像素之间的运算
于是要求

要求两张图象大小一致

API

add(src1, src2, dst=None, mask=None, dtype=None)        // +
multiply(src1, src2, dst=None, scale=None, dtype=None)	// -
subtract(src1, src2, dst=None, mask=None, dtype=None)	// x
divide(src1, src2, dst=None, scale=None, dtype=None)	// /

代码

#include <opencv2/opencv.hpp>
#include <iostream>

using namespace std;
using namespace cv;

int main(int argc, char** argv) {
    
    
	Mat src1, src2, dst;
	src1 = imread("C:/Users/86176/Pictures/pics/baboon.tiff");
	src2 = imread("C:/Users/86176/Pictures/pics/peppers(1).tiff");
	if (!src1.data) {
    
    
		cout << "could not load image which named boy.png..." << endl;
		return -1;
	}
	if (!src2.data) {
    
    
		cout << "could not load image named girl.png..." << endl;
		return -1;
	}

	double alpha = 0.5;
	if (src1.rows == src2.rows && src1.cols == src2.cols && src1.type() == src2.type()) {
    
    
		
		add(src1, src2, dst, Mat());
		//multiply(src1, src2, dst, Mat());
		//subtract(src1, src2, dst, 1.0);
		//divide(src1, src2, dst, 1.0);

		imshow("src1", src1);
		imshow("src2", src2);
		imshow("dst", dst);
	}
	else {
    
    
		printf("could not blend images , the size of images is not same...\n");
		return -1;
	}

	waitKey(0);
	return 0;
}

效果

src1

src2

加

减

乘

除