题目
BUPT 2018 计算机 ProblemB
用点阵表示数字，5*3的方格表示0~9，具体如下：
0的表示：
111
101
101
101
111
1的表示：
001
001
001
001
001
2的表示：
111
001
111
100
111
9的表示：
111
101
111
001
111
输入描述
输入一个数字串，用点阵输出。
输出描述
按题意输出
示例
输入
02
输出
111111
101001
101111
101100
111111
题解
刚开始没看懂这道题的01分布是什么规律，后来发现就是视觉上用1拼成的数字，然后就明白了这就是一道暴力题，没啥规律可言，一个一个写就行了
#include<bits/stdc++.h>
using namespace std;
int main()
{
string s;
cin>>s;
vector<vector<string>>number(10,vector<string>());
number[0]= {
"111","101","101","101","111"};
number[1]= {
"001","001","001","001","001"};
number[2]= {
"111","001","111","100","111"};
number[3]= {
"111","001","111","001","111"};
number[4]= {
"101","101","111","001","001"};
number[5]= {
"111","100","111","001","111"};
number[6]= {
"111","100","111","101","111"};
number[7]= {
"111","001","001","001","001"};
number[8]= {
"111","101","111","101","111"};
number[9]= {
"111","101","111","001","111"};
for(int i=0;i<5;i++)
{
for(int j=0;j<s.length();j++)
cout<<number[s[j]-'0'][i];
cout<<endl;
}
}
【注意】输入的string，单个元素是char，别忘了s[j]-'0'才能转成int
又忘记了，每次都因为这个找错耽误好多时间…