案例: 今天是12月08号 查询 12月1号到8号的访问量
create table user1(
id int primary key auto_increment,
name varchar(200),
create_date datetime
);
insert into user1 values(null,'zs','2020-12-01');
insert into user1 values(null,'zs','2020-12-01');
insert into user1 values(null,'zs','2020-12-01');
insert into user1 values(null,'zs','2020-12-02');
insert into user1 values(null,'zs','2020-12-02');
insert into user1 values(null,'zs','2020-12-02');
insert into user1 values(null,'zs','2020-12-02');
insert into user1 values(null,'zs','2020-12-03');
select * from user1;
select user1.name,days.day,count(user1.`name`) from (SELECT
date_add(DATE_ADD(curdate(), INTERVAL - DAY(curdate()) + 2 DAY),
INTERVAL (cast( help_topic_id AS signed INTEGER ) - 1 ) DAY
) DAY
FROM
mysql.help_topic
WHERE
help_topic_id < DAY ( curdate( ) )
ORDER BY
help_topic_id) days left join user1 on date(days.day) = date(user1.create_date) group by days.day,user1.name;