leetcode刷题(116)——反转字符串

编写一个函数,其作用是将输入的字符串反转过来。输入字符串以字符数组 char[] 的形式给出。

不要给另外的数组分配额外的空间,你必须原地修改输入数组、使用 O(1) 的额外空间解决这一问题。

你可以假设数组中的所有字符都是 ASCII 码表中的可打印字符。

示例 1:

输入:["h","e","l","l","o"]
输出:["o","l","l","e","h"]

示例 2:

输入:["H","a","n","n","a","h"]
输出:["h","a","n","n","a","H"]

非常简单,双指针交换数字就好了

class Solution {
    
    
    public void reverseString(char[] s) {
    
    
        int n = s.length;
        for (int left = 0, right = n - 1; left < right; ++left, --right) {
    
    
            char tmp = s[left];
            s[left] = s[right];
            s[right] = tmp;
        }
    }
}


猜你喜欢

转载自blog.csdn.net/u012124438/article/details/113825860