(1)9_4答案
bool lookfor_val ( vector<int>::iterator bn ,vector<int>::iterator ed,int val) { for (; bn!=ed; bn++) { if (*bn==val) { return true; break; } } return false; } int main() { vector<int> vec{1,2,3,4}; vector<int>::iterator begin = vec.begin(); vector<int>::iterator end = vec.end(); bool resault = lookfor_val(begin,end,0); cout << resault << endl; system("pause"); return 0; }
(2)9_5答案
vector<int>::iterator lookfor_val(vector<int>::iterator bn, vector<int>::iterator ed, int val) { vector<int>::iterator null = bn; for (; bn != ed; bn++) { if (*bn == val) { return bn; break; } } //cout << "没有要找得值" << endl;输出语句在主函数中处理 return ed;//怎么解决没有相等得值得情况 } int main() { vector<int> vec{ 1,2,3,4 }; vector<int>::iterator begin = vec.begin(); vector<int>::iterator end = vec.end(); int look_for_number = 0; if (lookfor_val(begin, end, look_for_number)!=end) { int resault = *lookfor_val(begin, end, look_for_number); cout << resault << endl; } else { cout << "没有要找的值" << endl; } system("pause"); return 0; }
(3)9_14答案
void main() { list<char* > li = {"wo","shi","shui"}; vector<string> str; str.assign(li.begin(),li.end()); for (auto c:str) { cout << c << endl; } system("pause"); return; }
(4)9_18答案
int main() { //在deque尾部添加元素 deque<string> deq; string str; cout << "please input the string" << endl; /*while (cin >> str) { deq.push_back(str); } for (auto c:deq) { cout << c << endl; }*/ //在deque首部添加元素 while (cin >> str) { deq.push_front(str); } for (deque<string>::iterator it = deq.begin(); it != deq.end();it++) { cout << *it << endl; } system("pause"); return 0; }(5) 9_20答案
int main() { list<int> li{1 ,2 ,3 ,4 ,5 ,6}; deque<int> deq1, deq2; for (list<int>::iterator it = li.begin(); it != li.end(); it++) { if ((*it)%2==0) { deq1.push_back(*it); } else { deq2.push_back(*it); } } for (auto c : deq1) { cout << "deq1="<<c << endl; } for (auto c : deq2) { cout << "deq2=" << c << endl; } system("pause"); return 0; }