Python字典实现伪切片

故事是从这里开始的… 在这里插入图片描述

早上起床看到一条评论,有点懵逼,字典切片?
查阅了一下Python资料,3.6版本的Python改写了dict的内部算法,3.6版本之前是无序的;
So,现在就是有序的啦,注意的是这个顺序是key的插入顺序;
但字典虽有序没下标怎么切片?list列表?
那就把key放进list里,利用list自身的截取方法切一下片!
再用截取后的key对新的字典赋值!
所以脑子一热就写了个字典切片1.0版本

# 字典切片1.0版本
def dictcut(dict, start, end):
    # 临时存放字典的key
    temp = list(dict.keys())
    # 返回一个字典
    result = {
    
    }
    #切列表里的key
    temp = temp[start:end]
    for i in range(len(temp)):
        #用切完后的key列表对新的字典赋值
        result[temp[i]] = dict.get(temp[i])
    return result
#原字典
dict = {
    
    "zero": "0", "one": "1", "two": "2", "three": "3", "four": "4"}
print("dict:", dict)
start = eval(input("起始位置:"))
end = eval(input("结束位置:"))
#调用切片方法
newdict =dictcut(dict, start, end)
print("dictcut(dict,%d,%d):" % (start, end), newdict)

然后运行结果

两个数为正,而且不越界,正常截取
如果我想从2截取到末尾,末尾坐标是-1,但传[2 : -1]就会截取[2,-1),截取不到最后一个;那如果传[2 : 0]就会像下面一样
所以list[2: ]截取从2到最后一个,在传参方面就显得很麻烦了
如果截取[-5,-3]没问题,但是[-3,-5]就不行了
综上,我希望我的字典切片可以三百六四度无死角切,从正到负,从前到后,正着切,逆着切

所以字典切片2.0版本就登场了!

# 字典切片2.0
def dictcut(dict, start, end):
    # 临时存放字典的key
    temp = list(dict.keys())
    # 返回一个字典
    result = {
    
    }
    # 分两个分支 1.start和end在可切片范围内 2.不在范围内
    if start <= len(temp) - 1 and start >= -len(temp) and end <= len(temp) - 1 and end >= -len(temp):
        #start大于end,且下标不重叠
        if start > end and start - 1 != len(temp) + end:
            #start和end同时为大于等于0
            if start >= 0 and end >= 0:
                # (4,2) 4 0 1
                for i in range(start, len(temp)):
                    result[temp[i]] = dict.get(temp[i])
                for i in range(0, end):
                    result[temp[i]] = dict.get(temp[i])
            # start和end同时小等于0
            if start <= 0 and end <= 0:
                # (-1,-3) 4 0 1
                for i in range(len(temp) + start, len(temp)):
                    result[temp[i]] = dict.get(temp[i])
                for i in range(0, len(temp) + end):
                    result[temp[i]] = dict.get(temp[i])
            # start大于0,end小于0
            if start >= 0 and end < 0:
                # (1,-2) 1 2
                for i in range(start, len(temp) + end):
                    result[temp[i]] = dict.get(temp[i])

        # end大于start,且下标不重叠
        elif end > start and start + len(temp) != end - 1:
            # start和end同时为大于等于0
            if start >= 0 and end >= 0:
                # (0,3) 0 1 2
                for i in range(start, end):
                    result[temp[i]] = dict.get(temp[i])
            # start和end同时大小等于0
            if start <= 0 and end <= 0:
                # (-4,-1) 1 2 3
                for i in range(len(temp) + start, len(temp) + end):
                    result[temp[i]] = dict.get(temp[i])
            # end大等于0,start小于0
            if end >= 0 and start < 0:
                # (-1,3) 4 0 1 2
                for i in range(len(temp) + start, len(temp)):
                    result[temp[i]] = dict.get(temp[i])
                for i in range(end):
                    result[temp[i]] = dict.get(temp[i])
        #start等于end,或者下标重叠
        elif end == start or start + len(temp) == end - 1 or end <= 0 and start - 1 == len(temp) + end:
            print("切了个寂寞！")
    # start或者end不在范围内
    else:
        print("传入参数有误！")
    return result
#原字典
dict = {
    
    "zero": "0", "one": "1", "two": "2", "three": "3", "four": "4"}
print("dict:", dict)
print("字典切割:左闭右开")
start = eval(input("起始位置:"))
end = eval(input("结束位置:"))
newdict = dictcut(dict, start, end)
# 如果返回的字典不为空，打印结果
if len(newdict) != 0:
    print("dictcut(dict,%d,%d):" % (start, end), newdict)

运行结果:

若不在范围
如果坐标重叠,重叠切个寂寞哦?
360°无死角切切切(正常切)
正数
负数

扫描二维码关注公众号，回复： 12044570 查看本文章
360°无死角切切切(从后往前切)
正数
负数

2.0代码比较繁琐,但是字典切片的效果还是清晰可见的~~~

Python字典实现伪切片

猜你喜欢