python笔记——enumerate,heapq,itertools,Counter用法

names=['关羽','张飞','赵云','马超','黄忠']
courses=['语文','数学','英语']
socres=[[None]*len(courses)for _ in range(len(names))]
print(socres)
for row,name in enumerate(names):
    for col,course in enumerate(courses):
        socres[row][col]=float(input(f'请输入{name}的{course}成绩:'))
        print(socres)



import heapq
list1=[34,25,12,99,87,63,58,78,88,92]
list2 = [
    {
    
    'name': 'IBM', 'shares': 100, 'price': 91.1},
    {
    
    'name': 'AAPL', 'shares': 50, 'price': 543.22},
    {
    
    'name': 'FB', 'shares': 200, 'price': 21.09},
    {
    
    'name': 'HPQ', 'shares': 35, 'price': 31.75},
    {
    
    'name': 'YHOO', 'shares': 45, 'price': 16.35},
    {
    
    'name': 'ACME', 'shares': 75, 'price': 115.65}
]
print(heapq.nlargest(3,list1))
print(heapq.nsmallest(3,list1))
print(heapq.nlargest(2,list2,key=lambda x:x['shares']))
print(heapq.nlargest(2,list2,key=lambda x:x['price']))


import  itertools
itertools.combinations('ABCD',3)

from collections import Counter
words = [
    'look', 'into', 'my', 'eyes', 'look', 'into', 'my', 'eyes',
    'the', 'eyes', 'the', 'eyes', 'the', 'eyes', 'not', 'around',
    'the', 'eyes', "don't", 'look', 'around', 'the', 'eyes',
    'look', 'into', 'my', 'eyes', "you're", 'under'
]
counter=Counter(words)
print(counter)
print(counter.most_common(5))