Oracle练习题答案

练习题

   1.  select DEPTNO from DEPT ;
   2. select DEPTNO from EMP ;
   3. select DISTINCT “JOB” from EMP ;
   4.  select * from EMP where SAL>2000;
   5. select ENAME,EMPNO,SAL from EMP where DEPTNO=20;
   6. select * from EMP where (COMM is NULL OR COMM = 0);
   7.  select * from EMP where (COMM is NOT NULL );
   8. select * from EMP where MGR is NULL;
   9. select * from EMP where HIREDATE >= “TO_DATE”(‘1981-01-01’,’yyyy-mm-dd’); 
       select * from EMP where HIREDATE >= ‘1-1月-81’;
   10. select * from EMP where SAL BETWEEN 2000 AND 4000;
   11. select * from EMP where DEPTNO IN (10,30);
   12. select * from EMP where DEPTNO = 20 AND SAL > 2000;
   13. select * from EMP where SAL NOT BETWEEN 2000 AND 4000;
   14. select * from EMP where DEPTNO NOT IN (10,30);
   15.  select * from EMP where ENAME = ‘SCOTT’;
   16.  select ENAME from EMP WHERE ENAME LIKE ‘%ALL%’;
   17.  select * from EMP WHERE ENAME LIKE ‘S%’;
   18.  select ENAME from EMP WHERE ENAME LIKE ‘_A%’;
   19.  select EMPNO,ENAME,DEPTNO,”JOB”,SAL from EMP ORDER BY SAL DESC;
   20.  select * from EMP ORDER BY DEPTNO DESC,SAL ASC;
   21.  select ENAME,EMPNO,SAL from EMP WHERE ENAME LIKE ‘%A%’ ORDER BY SAL DESC;
   22. SELECT ENAME,EMPNO,SAL,(SAL+”NVL”(COMM, 0))*12 AS YEARSAL 
        FROM EMP WHERE (SAL+”NVL”(COMM, 0))*12 > 10000 ORDER BY YEARSAL DESC;
   23. SELECT ENAME,EMPNO,SAL,SAL*12 AS YEARSAL 
        FROM EMP WHERE SAL*12 > 10000 ORDER BY YEARSAL DESC;
   24. SELECT ROUND((SYSDATE-HIREDATE)/7) AS “Weeks” FROM EMP WHERE ENAME = ‘SMITH’;
   25.  SELECT DEPTNO,”MAX”(SAL),”MIN”(SAL),”AVG”(SAL) FROM EMP GROUP BY DEPTNO;
   26.  SELECT ENAME FROM EMP WHERE EMPNO = (SELECT MGR FROM EMP WHERE ENAME = ‘SMITH’);
   27. SELECT * FROM EMP WHERE DEPTNO = (SELECT DEPTNO FROM DEPT WHERE DNAME = ‘SALES’);
   28.  SELECT * FROM EMP WHERE SAL = (SELECT “MAX”(SAL) FROM EMP);
   29.  SELECT “COUNT”(ENAME) FROM EMP ;
   30. SELECT “MAX”(SAL) FROM EMP ;
   31.  SELECT “AVG”(“NVL”(COMM, 0)) FROM EMP ;
   32.  SELECT “MAX”(HIREDATE) FROM EMP ;
   33.  SELECT “COUNT”(ENAME) FROM EMP WHERE (COMM IS NOT NULL) ;
   34.  SELECT “MAX”(SAL) FROM EMP WHERE DEPTNO = 20 ;
   35.  SELECT “AVG”(SAL),DNAME,EMP.DEPTNO FROM EMP,DEPT where EMP.DEPTNO = DEPT.DEPTNO GROUP BY DNAME,EMP.DEPTNO;
   36.  select empno , ename,DEPTNO from emp WHERE SAL in (select “MAX”(SAL) from EMP GROUP BY DEPTNO);
   37.  SELECT “MAX”(SAL) FROM EMP WHERE ENAME LIKE ‘%A%’ ;
   38.  SELECT “MAX”(SAL),”MIN”(SAL) FROM EMP WHERE SAL > 1000 GROUP BY “JOB”;
   39. SELECT AVG(SAL),DEPTNO FROM EMP GROUP BY DEPTNO HAVING AVG(SAL) > 2000;
   40.  SELECT AVG(SAL),DEPTNO FROM EMP where ENAME LIKE ‘%A%’ GROUP BY DEPTNO HAVING AVG(SAL) > 1500 ORDER BY AVG(SAL) DESC;
   41.  select * from EMP where (deptno,SAL) in (select deptno,MAX(sal) from emp GROUP BY DEPTNO);
   42.  SELECT * FROM EMP WHERE SAL = (SELECT “MAX”(SAL) FROM EMP);
   43.  select * from emp e1 where sal > ( 
        select avg(sal) from emp e2 where e1.deptno = deptno 
        );
   44.  SELECT * FROM EMP WHERE SAL = (SELECT “MAX”(SAL) FROM EMP); 
   45. select * from EMP where (deptno,SAL) in (select deptno,MAX(sal) from emp GROUP BY DEPTNO);
   46. select ENAME from EMP where EMPNO = (select MGR from EMP where ENAME = ‘SMITH’) ;
   47. select * from EMP where DEPTNO = (SELECT DEPTNO FROM DEPT WHERE dname = ‘SALES’) ;
   48.  select * from EMP where SAL = (SELECT MAX(SAL) FROM EMP) ;
   49.  select * from emp where sal between 
        (select LOSAL from salgrade where grade = 4) AND 
        (select HISAL from salgrade where grade = 4) ;
   50.  select * from emp where MGR = (select EMPNO from emp where ENAME = ‘BLAKE’);
   51.  select grade FROM SALGRADE where (SELECT SAL from emp where mgr is NULL) BETWEEN LOSAL AND HISAL;
   52.  select * from emp where SAL = (select MIN(sal) from emp);
   53.  select * from emp where JOB = (select JOB from emp where ENAME = ‘SMITH’) ;
   54. select * from emp e1 where not EXISTS 
        (select * from emp e2 where e2.mgr = e1.empno);
   55.  select deptno from emp group by deptno having avg(sal) < 
        (select avg(sal) from emp where deptno = 10);
   56. select * from EMP where DEPTNO = (select DEPTNO from DEPT where LOC = ‘NEW YORK’);
   57. select grade from SALGRADE where 
        (select AVG(SAL) from emp where DEPTNO = 
        (select DEPTNO FROM DEPT WHERE dname = ‘SALES’) ) BETWEEN LOSAL AND HISAL;
   58. select (select COUNT(DEPTNO) from EMP where DEPTNO = 10) / (select COUNT(*) from EMP) FROM dual;
   59.  select rownum rn,EMP.* from emp where rownum <= 5；select * from 
        (select rownum rn,EMP.* from emp where rownum <= 10) 
        where rn > 5; select emp.* from 
        (select rownum rn,t1.* from 
        (select * from emp order by sal desc) t1 
        where rownum <= 10) emp 
        where rn > 5;
   60. select * from emp e1 where sal > ( 
        select avg(sal) from emp e2 where e1.deptno = deptno 
        );
   61. select * from emp e1 where sal < (select avg(sal) from emp e2 where e1.job= job group by job);
   62.  select * from emp e1 where EXISTS 
        (select * from emp e2 where e2.mgr = e1.empno);
   63. select ename,sal,dname from emp,dept where EMP.DEPTNO = DEPT.DEPTNO;
   64. select ename,sal,dname,grade from emp,dept,SALGRADE 
        where EMP.DEPTNO = DEPT.DEPTNO and SAL BETWEEN LOSAL AND HISAL;
   65.  select a.ename AS 员工姓名 ,b.ename AS 领导姓名 
        from emp a LEFT JOIN emp b on a.mgr = b.empno;
   66. select ename, dname from emp ,dept where EMP.deptno = DEPT.deptno;
   
   
   
   1. select ename,sal from emp where sal > 1600;
   2.  select ename,deptno from emp where empno = 17;
   3. select ename,sal from emp where sal not BETWEEN 4000 and 5000;
   4.  select ename,deptno from emp where deptno in (20,30);
   5.  select ename,job from emp where mgr is null ORDER BY job asc;
   6.  select ename,sal,comm from emp where comm is not null ORDER BY sal asc;
   7. select ename from emp where ename like ‘__A%’;
   8.  select dname,loc from dept ;
   9.  select DISTINCT job from emp ;
   10. select ename ||’,’|| job ||’,’|| sal AS ename_job_sal from emp ;
   11.  select empno ,ename,sal ,sal*1.2 from emp ;
   12.  select empno ,sal,HIREDATE from emp where sal > 1200 ORDER BY HIREDATE ;
   13.  select dname from dept where dname != ‘ACCOUNTING’;
   14. select MAX(sal),deptno from emp where ename not like ‘_A%’ GROUP BY deptno having avg(sal) > 3000 ;
   15. select ename ,dname,grade from emp,dept,salgrade 
        where job = ‘MANAGER’ and (sal BETWEEN LOSAL and HISAL) 
        and EMP.DEPTNO = DEPT.DEPTNO;
   16. select max(sal),min(sal),avg(sal) from emp where sal > 1200 
        group by deptno having avg(sal) > 1500 order by avg(sal) DESC;
   17.  select ename from emp where sal = (select max(sal) from emp);
   18. select grade from salgrade s join 
        (select avg(sal) avg_sal from emp e group by deptno) temp 
        on TEMP.avg_sal between s.LOSAL and s.HISAL;
   19. select * from emp where ename like ‘S%’ or ename like ‘s%’;
   20. select empno,ename,TO_CHAR(HIREDATE,’yyyy”年”MM”月”dd”日”’) from emp where 
        TO_CHAR(SYSDATE,’YYYY’) - TO_CHAR(hiredate,’YYYY’) > 1;
   21. select ename,sal+NVL(comm, 0) from emp where deptno = 20 ;
   22. select * from emp where deptno = 10 and sal > 3000 ORDER BY HIREDATE ;
   23.  select SUBSTR(ename, 1, 3) from emp where deptno in (20,10) ORDER BY ename ;
   24. select lower(ename),TOCHAR(HIREDATE,′YYYY−MM−DD′),TOCHAR(sal,′99,999.999’) from emp ;
   25. select e1.ename,DEPT.dname,e1.sal,grade,e2.ename AS leader from emp e1,emp e2,dept,salgrade 
        where nvl(e1.MGR,0) = e2.empno and (e1.sal between SALGRADE.LOSAL and SALGRADE.HISAL) 
        and e1.deptno = dept.deptno;
   26. select ename,grade from emp ,salgrade ,dept where 
        dname=’ACCOUNTING’ and sal between LOSAL and HISAL 
        and EMP.deptno = DEPT.deptno ;
   27. select sal from emp where sal >= all (select sal from emp);