题目
Given two sorted integer arrays nums1 and nums2, merge nums2 into nums1 as one sorted array.
Note:
The number of elements initialized in nums1 and nums2 are m and n respectively.
You may assume that nums1 has enough space (size that is greater or equal to m + n) to hold additional elements from nums2.
Example:
Input:
nums1 = [1,2,3,0,0,0], m = 3
nums2 = [2,5,6], n = 3
Output: [1,2,2,3,5,6]
思路
直接输入的是vector类型的数组,因此直接利用stl库实现:
1.删除nums1中多余的0。
2.将nums2插入nums1尾部。
3.对nums1重新排序。
代码
class Solution {
public:
void merge(vector<int>& nums1, int m, vector<int>& nums2, int n) {
nums1.erase(nums1.end()-n,nums1.end());
nums1.insert(nums1.end(),nums2.begin(),nums2.end());
sort(nums1.begin(),nums1.end());
}
};