题目描述
输入一个8位数字和指定剔除的位数,将剩余数字从大到小打印。若不符合要求则打印error
如:输入95137462 2,则输出9764321
如:输入95137462 9, 则输出error
如:输入95137462123 1 则输出error
代码写的比较啰嗦,还可以再简化,第一次调试成功,仅仅就想纪念一下
#include<stdio.h>
#include<stdlib.h>
int cmp(const void* a, const void* b)
{
return *(int*)b - *(int*)a;
}
int main(void)
{
int num, n;
scanf("%d %d", &num, &n);
if (n < 1 || n > 8)
{
printf("error");
return 0;
}
int* arr = (int*)calloc(8, sizeof(int));
for (int i = 0; i < 8; i++)
{
arr[i] = num % 10;
num = num / 10;
}
if (num != 0)
{
printf("error");
return 0;
}
int* arrr = (int*)calloc(8, sizeof(int));
for (int i = 0, j = 7; i < 8, j >= 0; ++i, --j)
{
arrr[i] = arr[j];
}
int* arrs = (int*)calloc(7, sizeof(int));
int k = 0;
for (int i = 0; i < n - 1; i++)
{
arrs[k++] = arrr[i];
}
for (int i = n; i < 8; i++)
{
arrs[k++] = arrr[i];
}
qsort(arrs, 7, sizeof(int), cmp);
for (int j = 0; j < 7; j++)
{
printf("%d", arrs[j]);
}
return 0;
}