原题传送门
贪心,只给与叶子结点相连的边赋值,平均分
假设有
个叶子,每条叶子边的权值为
答案是
Code:
#include <bits/stdc++.h>
#define maxn 100010
using namespace std;
double s, cnt;
int n, d[maxn];
inline int read(){
int s = 0, w = 1;
char c = getchar();
for (; !isdigit(c); c = getchar()) if (c == '-') w = -1;
for (; isdigit(c); c = getchar()) s = (s << 1) + (s << 3) + (c ^ 48);
return s * w;
}
int main(){
n = read(), s = read();
for (int i = 1; i < n; ++i) ++d[read()], ++d[read()];
for (int i = 1; i <= n; ++i) cnt += (d[i] == 1);
printf("%.12lf\n", 2.0 * s / cnt);
return 0;
}