数据结构-实现后缀表达式计算(简单)

因为实在是太简单我就不讲了，可以点赞，给个鼓励
代码如下：

#include<stdio.h>
#define MAX 20
int main()
{
 char s1[MAX] = { '6','5','2','3','+','8','*','+','3','+','*','\0'};
 double s2[MAX] = { 0 };
 int i = 0;
 int j = 0;
 while (s1[i] != '\0')
 {
  if (s1[i] >= 48 && s1[i] <= 57)
  {
   s2[j++] = s1[i++] - 48.0;
  }
  else
  {
   switch (s1[i])
   {
   case '+':
    {
     s2[j-2]=s2[j-1] + s2[j-2];
     j = j - 1;
     i++;
     break;
    }
    
   case '*':
    {
     s2[j - 2] = s2[j - 1] * s2[j - 2];
     j = j - 1;
     i++;
     break;
    }
    
   case '/':
    {
     s2[j - 2] = s2[j - 1] / s2[j - 2];
     j = j - 1;
     i++;
     break;
    }  
   case '-':
    {
     s2[j - 2] = s2[j - 1] - s2[j - 2];
     j = j - 1;
     i++;
     break;
    }    
   }
  }   
 }
 printf("计算的结果是: %.0lf", s2[0]);
 return 0;
}

运行截图：