剑指 Offer 25. 合并两个排序的链表

剑指 Offer 25. 合并两个排序的链表

难度简单36收藏分享切换为英文关注反馈

输入两个递增排序的链表,合并这两个链表并使新链表中的节点仍然是递增排序的。

示例1:

输入:1->2->4, 1->3->4
输出:1->1->2->3->4->4

限制:

0 <= 链表长度 <= 1000

class Solution {
    public ListNode mergeTwoLists(ListNode l1, ListNode l2) {
        if (l1 == null) {
            return l2;
        }
        if (l2 == null) {
            return l1;
        }
        ListNode dummy = new ListNode(-1);
        ListNode p = dummy;
        while (l1 != null && l2 != null) {
            if (l1.val <= l2.val) {
                p.next = l1;
                l1 = l1.next;
            } else {
                p.next = l2;
                l2 = l2.next;
            }
            p = p.next;
        }
        if (l1 != null) {
            p.next = l1;
        }

        if (l2 != null) {
            p.next = l2;
        }
        return dummy.next;
    }
}

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转载自blog.csdn.net/ZhaoXia_hit/article/details/107396395