订单表（ dt, uid, course, price ）, 求每天购课总额前三的用户
dt |
uid |
course |
price |
2019-01-01 |
1 |
数学 |
50 |
2019-01-01 |
2 |
数学 |
20 |
2019-01-01 |
2 |
语文 |
30 |
2019-01-01 |
3 |
语文 |
40 |
2019-01-02 |
1 |
语文 |
10 |
2019-01-02 |
1 |
英语 |
30 |
2019-01-03 |
1 |
数学 |
40 |
with tbl_order as
(
select '2019-01-01' as dt, 1 as uid, '数学' as course_id, 50 as price union all
select '2019-01-01' as dt, 2 as uid, '数学' as course_id, 50 as price union all
select '2019-01-01' as dt, 3 as uid, '数学' as course_id, 50 as price union all
select '2019-01-01' as dt, 4 as uid, '数学' as course_id, 50 as price union all
select '2019-01-01' as dt, 1 as uid, '数学' as course_id, 50 as price union all
select '2019-01-01' as dt, 1 as uid, '数学' as course_id, 50 as price union all
select '2019-01-01' as dt, 1 as uid, '数学' as course_id, 50 as price union all
select '2019-01-01' as dt, 1 as uid, '数学' as course_id, 50 as price
)
select dt, uid
from(
select dt, uid, sum(price), rank() over (partition by dt order by sum(price) desc) as rk
from tbl_order
group by dt,uid
) a
WHERE rk >= 3