#include <stdio.h>
void main() {
char s[10];
int i, n;
gets(s);
for (n = i = 0; s[i] != '\0'; i++) {
if (s[i] >= '0' && s[i] <= '9')
n = n * 16 + s[i] - '0';
if (s[i] >= 'a' && s[i] <= 'z')
n = n * 16 + s[i] - 'a' + 10;
if (s[i] >= 'A' && s[i] <= 'Z')
n = n * 16 + s[i] - 'A' + 10;
}
printf("%d", n);
}
输入一个十六进制字符串,将其转换为对应的十进制。
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转载自blog.csdn.net/qq_38490457/article/details/105868765
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