面试题总结

1、有字符串"k:1|k1:2|k2:3|k3:4" 处理成字典 {'k':1,'k1':2....}
dic = "k:1|k1:2|k2:3|k3:4".split("|")
l = {}
for i in dic:l[i.split(":")[0]] = i.split(":")[1]
print(l)
#{'k':1,'k1':2....}

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转载自www.cnblogs.com/pupilheart/p/8992293.html