数据结构与算法(Java) 27:打印两个有序链表的公共部分

题目 给定两个有序链表的头指针head1和head2,打印两个 链表的公共部分。 

思路 类似与归并排序中的外排。

package algorithm.section4;

public class PrintCommonPart {
    public static class Node{
        int value;
        Node next;

        public Node(int value){
            this.value = value;
        }
    }

    public static void commonPart(Node head1, Node head2){
        while (head1 != null && head2 != null){
            if (head1.value == head2.value){
                System.out.print(head1.value + " ");
                head1 = head1.next;
                head2 = head2.next;
            }
            else if (head1.value < head2.value)
                head1 = head1.next;
            else head2 = head2.next;
        }
    }

    public static void main(String[] args){
        Node node1 = new Node(1);
        node1.next = new Node(2);
        node1.next.next = new Node(3);
        node1.next.next.next = new Node(6);

        Node node2 = new Node(2);
        node2.next = new Node(6);
        node2.next.next = new Node(7);

        commonPart(node1, node2);
    }
}
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转载自blog.csdn.net/Dorothy_Xue/article/details/105695314