二叉树的镜像(C 牛客网)

解题思路:

(1)首先交换左右孩子

(2)递归交换

/*
struct TreeNode {
	int val;
	struct TreeNode *left;
	struct TreeNode *right;
	TreeNode(int x) :
			val(x), left(NULL), right(NULL) {
	}
};*/
class Solution {
public:
    void Mirror(TreeNode *pRoot) {
        if(pRoot) {
            TreeNode *temp = pRoot->left;
            pRoot->left = pRoot->right;
            pRoot->right = temp;
            Mirror(pRoot->left);
            Mirror(pRoot->right);
        }

    }
};
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转载自blog.csdn.net/coolsunxu/article/details/105668170