2015-1

/*
2020/4/17
第二遍
*/
#include <iostream>
#include<stdio.h>
using namespace std;

int n1,result1;
int n2,result2;
int factor[100];
int count = 0;

int fun(int n)
{
    int result = 0;
    for(int i = 1;i<=n/2;i++)//for(int i = 0;i<=n/2;i++)***********如果需要做求余或者除法运算一定需要注意除数为0的情况
    {
        if(n%i == 0)
        {
            result+=i;
            factor[count++] = i;
            //printf("%d\n",i);
        }
    }
    return result;
}

int main()
{
    scanf("%d%d",&n1,&n2);

    count = 0;
    result1 = fun(n1);
    printf("%d,",n1);
    for(int i = 0;i<count;i++)
    {
        if(i == count - 1)
            printf("%d=%d\n",factor[i],result1);
        else printf("%d+",factor[i]);
    }

    count = 0;
    result2 = fun(n2);
    printf("%d,",n2);
    for(int i = 0;i<count;i++)
    {
        if(i == count - 1)
            printf("%d=%d\n",factor[i],result2);
        else printf("%d+",factor[i]);
    }

    if(n1 == result2 && n2 == result1)
        printf("1\n");
    else
        printf("0\n");

    return 0;
}
/*
IN:
220 284
OUT:
220,1+2+4+5+10+11+20+22+44+55+110=284
284,1+2+4+71+142=220
1
*/