输入一棵二叉搜索树,将该二叉搜索树转换成一个排序的双向链表。要求不能创建任何新的结点,只能调整树中结点指针的指向
/**
public class TreeNode {
int val = 0;
TreeNode left = null;
TreeNode right = null;
public TreeNode(int val) {
this.val = val;
}
}
*/
public class Solution {
public TreeNode Convert(TreeNode pRootOfTree) {
if(pRootOfTree==null)
return null;
if(pRootOfTree.left==null&&pRootOfTree.right==null)
return pRootOfTree;
TreeNode left = Convert(pRootOfTree.left);
TreeNode p = left;
while(p!=null&&p.right!=null)
p=p.right;
if(left!=null){
p.right=pRootOfTree;
pRootOfTree.left=p;
}
TreeNode right = Convert(pRootOfTree.right);
if(right!=null){
pRootOfTree.right=right;
right.left=pRootOfTree;
}
return left!=null?left:pRootOfTree;
}
}