反转一个单链表。
示例:
输入: 1->2->3->4->5->NULL 输出: 5->4->3->2->1->NULL
进阶:
你可以迭代或递归地反转链表。你能否用两种方法解决这道题?
非递归实现:
/**
* Definition for singly-linked list.
* public class ListNode {
* int val;
* ListNode next;
* ListNode(int x) { val = x; }
* }
*/
class Solution {
public ListNode reverseList(ListNode head) {
ListNode reversedHead = null;
ListNode temp = head;
ListNode pre = null;
while(temp!=null) {
ListNode next = temp.next;
if(next==null) {
//到尾部了
reversedHead = temp;
}
temp.next = pre;
pre = temp;
temp = next;
}
return reversedHead;
}
}
递归实现:
/**
* Definition for singly-linked list.
* public class ListNode {
* int val;
* ListNode next;
* ListNode(int x) { val = x; }
* }
*/
class Solution {
public ListNode reverseList(ListNode head) {
if(head ==null || head.next ==null) {
return head;
}
ListNode node = reverseList(head.next);
head.next.next = head;
head.next = null;
return node;
}
}