About i ++ and ++ i

 

Look at the code, guess what output value

@Test 
public void Test () { 
    int I =. 1; 
    int A, B = 0; 
    I ++; 
    A = (I ++); 
    System.out.println (A); 
    System.out.println (I); 
    the System.out. the println (B ++); 
    System.out.println (B ++); 

    for (int = 0 K; K <. 5; K ++) { 
        System.out.println (K); 
    } 
    for (int = S 0; S <. 5 ; S ++) { 
        System.out.println (S); 
    } 
} 

The following comments about I added, the final paste at the output

@Test 
public void the Test () { 
    int i = 1; // define a variable i, ++ operation is only possible after initialization, otherwise it will compile error 
    int a, b = 0; // definition of a and b, a not initialize 
    i ++; // i automatic execution + 1'd 
    a = (I +); // assigned to I a, the place with the place there is a difference, a is the assignment is obtained before ++, and not because of the increase in brackets +1 on the first execution after the assignment 
    System.out.println (A); 
    System.out.println (I); 
    System.out.println (B ++); 
    System.out.println (B ++); 

    for (int K 0 =; K <. 5; K ++) { 
        System.out.println (K); 
    } 
    for (int = S 0; S <. 5; S ++) { 
        System.out.println (S); 
    } 
} 

As a result, you counting on you

1
2
0
2
0
1
2
3
4
0
1
2
3
4

Process finished with exit code 0