I do not open $ C 11 $ ++ compiler I will jump from the third floor $$ \ text {%%% lsc} $$
Day3
-lm -O2 -std=c++11
Before
Day3?
All Subtask?
1/4？
T1
matrix?
Well, I have a point of zero does not burst the =. =
T2
3 seconds
Not afraid of death ......
Do not be afraid of life ......
...... reservation data structure
T3
As if the original title, kuku a (not QnQ)
Not ah, requiring become more ......
lsc should have died? ? (Face purple).
During
T1
If there is no overlap directly engage the answer just fine ......
In fact,
And the meaning is as if Yihuo
The last count the number of occurrences of an odd number of XOR and ......
Input
10 4 1 1 10 1 5 5 4 4 1 9 4 3 3 3 5 2
Output
0
sth.
1 0 0 0 0 0 0 0 3 0 1 1 0 0 0 0 0 0 3 3 1 1 3 0 0 0 0 0 3 3 1 1 3 3 0 0 0 0 3 3 1 1 3 3 7 0 0 0 0 0 1 1 3 3 7 7 0 0 0 0 1 1 3 3 7 7 7 0 0 0 1 1 1 1 5 5 5 5 0 0 1 1 1 1 1 1 1 1 1 0 1 1 1 1 1 1 1 1 1 1
Suddenly thought of difference ...... emm
We need three different differential?
You can also change the two kinds?
We have to try ......
If it becomes, Complexity:
O(q+n^2)
Over, pan ......
There has been a prefix and staggered ......
The difficulty of the questions that \ times \ triangle of two-dimensional differential times
There will be piles of repeat ......
Solve a ......
Minute direction update?
Well, all deal with the QwQ
cerr to output 3s dumbfounding
Measured for a long time and found very slow,
Later found that the measured time violence ......
Take a long time did not find time to open seed ......
T2
Tribute to WWB! (fog
Went 2 ^ 30 need 2.143s
Enumeration random numbers?
Factorial complexity banrbi bombing
If the walking DP ...... + Qj = Subtask 1 ~ 4
Acquire two points ......
emm
Set f [s] for a selection contribution is s.
count (s) updated the answer when == k ......
You must be updated in order count of ......
He wrote knelt over.
T3
Here there are 1 minute ......
So a total of four points?
This question is what the tree dp ......
greedy?
Dichotomy?
Result&After
|
15
|
Miemeng | 100
03:12:59
|
2
03:14:00
|
1
03:14:02
|
103
03:14:02
|
Dy4
Get two good character: Cheese Li
Before
T1
Oh if it is the DP title
T2
matrix……
T3
And Azerbaijan have relations?
First simulate it, looking at it cancer?
During
T1
Product coprime sides, so both sides of the factor must be different
Thus the number of each factor determination Laid decomposed and $ 1 $
So $ ^ 6 $ 10 at most some number of different factors that $ 7 $ more ......
$$
\begin{array}{rcl}
2 \times 3 \times 5 \times 7 \times 11 \times 13 \times 17 &=& 510510 \\
2 \times 3 \times 5 \times 7 \times 11 \times 13 \times 17 \times 19 & = & 9699690
\end{array}
$$
By a factor of direct enumeration subset ......
$3^7$ ?
This……
Te摸 best ......
Like the line?
Mainly to do with every number restrictions
As well as the rest of the factor (if does not make sense ......)
First decomposition and the quality factor is larger than $ \ sqrt {a_i} $ row outside ......
There is relatively little violence feasible:
First of all to the decomposition pressure of a bucket of factors.
Every enumeration subset factor ...... and then pick up all the numbers ......
$ O (2 ^ PN) $ (more preferably only) $ P $: a different number of factors ......
First on a no brain violence ......
Probably, there has been an idea,
All the numbers are multiplied together to seek a total of prime factors
Inclusion and exclusion then calculated for each occurrence factor
Finally, the situation can not be subtracted ......
Complexity is like $ N ^ 2 $ of?
Code is not enough ah $ QAQ $
Various YY:
First of all may know, two of the same number with a certain in the collection (except 1)
Then greater than $ \ sqrt {a_i} $ is the unique prime factor (a number on a) ......
The remaining prime factors also $ 168 $ months.
The remaining number will be less than $ 168 + with the complexity of the intersection of N $ judgments ......
If there is no duplication and the rest, you can directly persimmon count.
As long as the judge sentenced to pay fine.
Sentenced to pay can also directly maintain gcd.
Prime factor decomposition treatment pressure vector, $ \ Theta (N * logM) $ and each vector maintains $ gcd $.
Point out the pot ......
T2
Think about how fucks ......
Memories of?
Now think back to the path of each point of the cycle can be directly processed.
Each point is able to contribute as if only two points, so in the end is actually a binary tree ......
The tree can be built to ensure that strange little complexity.
Since d is 20, the layer 20 is sufficient to build.
So now how to build ah $ QAQ $
If violence was built ...... $ 2 ^ N $?
We now need to know that there is no node just fine ......
It is actually a side of the point? ?
ST imitation at the table ......
Or complexity of terror.
T3
There are 1 minute $ QvQ $
Feel weird ......
There is no master card often over $ N ^ 2 $ $ $ 100000
Finished, I was not thinking of ......
Because to simulate this process, so the speculation of violence card card is very strict ......
The next step is to get a single increase of $ Subtask $
Feel can be created to reflect the length of the record ...... 800 word reflection to find out ......
Kneeling ......
After
|
47
|
Miemeng | 0
03:14:37
|
21
03:14:38
|
31
03:14:38
|
52
03:14:38
|
See the magical colors of the T1 Well ...... CE ......
to sum up:
Day3 okay, I can also think of
Day4 knees.
Stick to something here:
/sandbox/1/a.cpp:11:9: error: 'long long int div [2]' redeclared as different kind of symbol
LL div[2];
^
In file included from /usr/include/c++/5/cstdlib:72:0,
from /usr/include/c++/5/ext/string_conversions.h:41,
from /usr/include/c++/5/bits/basic_string.h:5249,
from /usr/include/c++/5/string:52,
from /usr/include/c++/5/bits/locale_classes.h:40,
from /usr/include/c++/5/bits/ios_base.h:41,
from /usr/include/c++/5/ios:42,
from /usr/include/c++/5/ostream:38,
from /usr/include/c++/5/iostream:39,
from /sandbox/1/a.cpp:1:
/usr/include/stdlib.h:788:14: note: previous declaration 'div_t div(int, int)'
extern div_t div (int __numer, int __denom)
^
div knelt ...... emm
Please open $ C ++ 11 $ compiler $ \ text {T_T} $
Talk about: Be sure to define the variables used in the order ah ......
$$\Huge \text{ %%%$\frac{1}{4}$}$$