1. grammar G (Z): Z-> aZb | ab definition of what kind of language?
From the meaning of the questions: Z-> aZb or Z-> ab
Z->ab,Z->aZb->aabb,Z->aZb->aaZbb->aaabbb,Z->aZb->aaZbb->aaaZbbb->aaaabbbb
Z=>aZb=>a²Zb²...=>aⁿ﹣¹Zbⁿ﹣¹=>aⁿbⁿ
Therefore, L (G [Z]) = {aⁿbⁿ | n≥1}
2, p. 22 write grammar textbook example 2.2 identifier quadruple form .
Provided: an identifier represented by A, represented by the letter B: A-> a | b | ... | z, is represented by C number: C-> 0 | 1 | ... | 9
VN={A,B,C}、VT={a,b,c,…,x,y,z,0,1,…,9}
P={ A->B,A->AB,A->AC;
B->a
…
B->z
C->0
…
C->9 }
S=<A>
3. Write the following expressions leftmost derivation and rightmost derivation syntax tree.
G (E):
E=> E + T | T
T=>T * F | F
F=>(E)| i
- i*i+i
- i+i*i
- i+(i+i)
Observe the leftmost and rightmost derivation is different, and the similarities and differences between the syntax tree
(1)i*i+i
最左推导:E=>E+T=>T+T=>T*F+T=>F*F+T=>i*i+T=>i*i+F=>i
最右推导:E=>E+T=>E+F=>E+i=>T+i=>T*F+i=>T*i+i=>F*i+i=>i*i+i
Syntax tree:
(2)i+i*i
最左推导:E=>E+T=>T+T=>F+T=>i+T=>i+T*F=>i+F*F=>i+i*F=>i+i*i
最右推导:E=>E+T=>E+T*F=>E+T*i=>E+F*i=>E+i*i=>T+i*i=>F+i*i=>i+i*i
Syntax tree:
(3)i+(i+i)
最左推导:E=>E+T=>T+T=>F+T=>i+T=>i+F=>i+(E)=>i+(E+T)=>i+(T+T)=>i+(F+T)=>i+(i+T)=>i+(i+F)=>i+(i+i)
最右推导:E=>E+T=>E+F=>E+(E)=>E+(E+T)=>E+(E+F)=>E+(E+i)=>E+(T+i)=>E+(T+i)=>E+(F+i)=>E+(i+i)=>T+(i+i)=>F+(i+i)=>i+(i+i) 语法树: