(Easy) Ransom Note - LeetCode

Description:

Given an arbitrary ransom note string and another string containing letters from all the magazines, write a function that will return true if the ransom note can be constructed from the magazines ; otherwise, it will return false.

Each letter in the magazine string can only be used once in your ransom note.

Note:
You may assume that both strings contain only lowercase letters.

canConstruct("a", "b") -> false
canConstruct("aa", "ab") -> false
canConstruct("aa", "aab") -> true
Accepted
122,871
Submissions
242,605

Solution:

class Solution {
    public boolean canConstruct(String ransomNote, String magazine) {
        
            if((magazine==null|| magazine.length()==0)&&(ransomNote==null || ransomNote.length()==0)){
                return true;
            }
        
            if(ransomNote==null||ransomNote.length()==0){
                return true;
            }
        
        
        for(int i = 0; i < ransomNote.length(); i++){
            
            if(Count(ransomNote, ransomNote.charAt(i)) > Count(magazine, ransomNote.charAt(i))){
                return false;
            }
        }
        
        return true;
        
    }
    
    static int Count(String str, Character a){
        
        int count = 0; 
        
        for(int i = 0; i < str.length(); i++){
            
            if(str.charAt(i)==a){
                count++;
            }
        }
        
        return count; 
    }
}

 

 

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Origin www.cnblogs.com/codingyangmao/p/11495871.html