java factoring integers [] Facing a ten, get a place, ten, one hundred digital

Seeking a count of single digits, tens, hundreds digit and one thousand:

　　int num = 53;

　　int g = (num / 1)% 10; // bit

　　int s = (num / 10)% 10; // ten

　　int b = (num / 100)% 10; // one hundred

　　int b = (num / 1000)% 10; // one thousand

 1 amount = String.valueOf(this.dealAmountByXXQ(new BigDecimal(amount), new BigDecimal(100), new BigDecimal(900),5));
 2 
 3 /**
 4      * 如果是整百金额就减paramSub
 5      * @param amount
 6      * @param start
 7      * @param end
 8      * @return
 9      */
10     public static BigDecimal dealAmountByXXQ(BigDecimal amount, BigDecimal start, BigDecimal end,Integer paramSub) {
11         if (amount.compareTo(start) == -1) {
12             return amount;
13         }
14         if (amount.compareTo(end) == 1) {
15             return amount;
16         }
17         int amt = amount.intValue();
18         int sw = (amt / 10) % 10;
19         int gw = (amt / 1) % 10;
20         if (gw == 0 && sw == 0) {
21             amt -=paramSub;
22         }
23         return new BigDecimal(amt);
24     }