01 backpack
i- i-th former article, k- volume, a [i] - the volume of the i-th item, b [i] - i-th value of the goods
State transition equation: f [i] [k] = max (f [i-1] [k], f [i-1] [ka [i]] + b [i]);
#include<iostream> using namespace std; int f[1005][1005]; int main(){ int i,k,m,n,v,a[1005],b[1005]; cin>>m; while(m--){ cin>>n>>v; for(i=1;i<=n;i++) cin>>b[i];//价值 for(i=1;i<=n;i++) cin>>a[i];//体积 for(i=1;i<=n;i++) for(k=0;k<=v;k++) f[i][k]=0; for(i=1;i<=n;i++) for(k=0;k<=v;k++){ if(k-a[i]>=0&&f[i-1][k]<f[i-1][k-a[i]]+b[i]) f[i][k]=f[i-1][k-a[i]]+b[i]; else f[i][k]=f[i-1][k]; } cout<<f[n][v]<<endl; } return 0; }
Scroll array optimization
#include<iostream> using namespace std; int f[105][2]; int main(){ int i,k,m,n,v,a[1005],b[1005]; cin>>m; while(m--){ cin>>n>>v; for(i=1;i<=n;i++) cin>>b[i]; for(i=1;i<=n;i++) cin>>a[i]; for(i=1;i<=n;i++) for(k=0;k<=v;k++) { if(k-a[i]>=0&&f[k][(i-1)%2]<f[k-a[i]][(i-1)%2]+b[i]) f[k][i%2]=f[k-a[i]][(i-1)%2]+b[i]; else f[k][i%2]=f[k][(i-1)%2]; } cout<<f[v][(i-1)%2]<<endl; } return 0; }
A decreasing volume of the transition state
#include<iostream> using namespace std; int f[1005]; int main(){ int i,k,m,n,v,a[1005],b[1005]; cin>>m; while(m--){ cin>>n>>v; for(i=1;i<=n;i++) cin>>b[i];//价值 for(i=1;i<=n;i++) cin>>a[i];//体积 for(k=0;k<=v;k++) f[k]=0; for(i=1;i<=n;i++) for(k=v;k>=0;k--) if(k>=a[i]) f[k]=max(f[k],f[k-a[i]]+b[i]); cout<<f[v]<<endl; } return 0; }