The first work in three shifts 20

A, PTA operations summary

(A) the title is not too fat 7-4

　1, experiment code

#include <stdio.h>
int main()
{
    int a;
    float b;
    scanf("%d", &a);
    b=(a-100)*0.9*2;
    printf("%.1f",b);
    return 0;
}

　2, design ideas

　(1) described in the text

　　Step 1: Enter the frame;

　　Step Two: Define two variables: a represents the height, is defined as a positive integer int type, b represents the weight of said nominal height, output request is one decimal place, it is defined to float;

　　The third step: scanf calls a method of an input value, the input is an integer of "% d", a fetch address is assigned a & a;

　　The fourth step: calculation formula b = (a-100) * 0.9 * 2, to give the corresponding value b;

　　Step five: one decimal output requirements, so "% .1f", the print result calculated value of b;

　(2) Scheme

　3. Problems encountered this problem debugging process and solutions

　　The definition of a, b forget output when requirements are defined as int type, how to submit not right, after careful examination correct;

　　printf when forgotten, before the program will run error, the red line is the wrong place to write the missing, filled out after the first fight and the next frame;

　　Write error "% f" output, the output after the decimal point six zero, check the condition of the subject plus "% .1f" corrected later.

(B) the price ladder 7-1

　1, experiment code

#include<stdio.h>
int main(){
    float use,cost;
    scanf("%f",&use);
    if(use<=0){
        printf("Invalid Value!");
    }
    else if(use>0&&use<=50){
        cost=0.53*use;
        printf("cost = %.2f",cost);
    }
    else if(use>50){
        cost=0.53*50+(0.53+0.05)*(use-50);
        printf("cost = %.2f",cost);
    }
  
    return 0;
}

　2, design ideas

　(1) described in the text

　　　Step 1: Enter the frame;

　　　Step Two: Define two float variables, use for the month electricity consumption, cost of electricity represents cope value, defined as the float has a decimal type;

　　　The third step: use the input value;

　　　Step Four: Analyzing use Size: less than or equal to 0, the end of the determination, an output ,; greater than 0 and less than or equal to 50 into the formula "cost = 0.53 * use" get the value of the cost, the output end of cost; "Invalid Value!"

　　　　　　　use of greater than 50 "cost = 0.53 * 50 + (0.53 + 0.05) * (use-50)", and outputs the calculated cost program ends.

　(2) Scheme

　3. Problems encountered this problem debugging process and solutions

　　use and cost types are float, use the input format% f;

　　else-if the cycle, if the conditions are, the unconditional else;

　　Three cases are calculated and printed printf () output, the printf not use the same;

　　cost =% f, are spaces.

Second, the summary and study the progress bar

　1, (1) starting to learn C language, we first learn the basic print statements printf (), defines three types of variable data int, float, double, respectively applied to different types of data and output results,

　　　　　又学习了格式化输入函数scanf（），取被输入变量的地址为变量赋值，和输入多个数据，然后学习了计算分段函数的三种方法：if-else语句，嵌

　　　　　套if-else语句和else-if语句，三种逻辑运算符：与&&、或||、非！，定义字符型数据char，switch-case语句，还有最重要的是for循环结构。

　　　（2）在学习过程中紧跟老师的脚步，课下认真完成作业就能对所学知识基本掌握，但是总有很多小问题，比如定义类型不对，忘写分号，数和括号中间

　　　　　用*乘号连接等小细节不加注意就会程序错误，for循环相关知识还没掌握牢，打开运行框太多软件崩溃等情况都表明新手还没熟练。

　　　（3）多写程序多练习，熟能生巧；在写语句时先把框架打好，先写分号避免忘记；多做for循环相关题型；在写程序前先画流程图以便更加清晰的理解

　　　　　程序。

The first work in three shifts 20

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