public static void main(String[]args) {
int[] x = {1, 2, 3, 4};
int[] y ;
y = x;
x[1] = 11;
x = new int[2];
x[0]=99;
for (int i = 0; i < y.length; i++)
System.out.print(y[i] + " ");
System.out.println("");
for (int i = 0; i < x.length; i++)
System.out.print(x[i] + " ");
}
answer is
1 11 3 4
99 0
My question is I thought when you assign two arrays, they share the same changes since they are objects... like when I set x[1] = 11; it changed the value of y, so shouldn't y still be identical to x after changing it to a 2-sized array, or since I am changing the size they no longer point to the same address?
int[] x = {1, 2, 3, 4};
{1, 2, 3, 4} is allocated as an array. A reference to it is assigned to x.
int[] y ;
y = x;
A reference to that same array is assigned to y as well.
x[1] = 11;
The array that both x and y refer to is now {1, 11, 3, 4}.
x = new int[2];
A new array is allocated, due to Java semantics, as {0, 0}. A reference to it is assigned to x. Now x and y refer to two different arrays. There is no resizing being done.
x[0]=99;
The array referred to by x is changed, and now contains {99, 0}. This has nothing to do with the array y refers to, which is still happily {1, 11, 3, 4}.