offeltoffel :
How would I manage to perform math.ceil such that a number is assigned to the next highest power of 10?
# 0.04 -> 0.1
# 0.7 -> 1
# 1.1 -> 10
# 90 -> 100
# ...
My current solution is a dictionary that checks the range of the input number, but it's hardcoded and I would prefer a one-liner solution. Maybe I am missing a simple mathematical trick or a corresponding numpy function here?
jonrsharpe :
You can use math.ceil with math.log10 to do this:
>>> 10 ** math.ceil(math.log10(0.04))
0.1
>>> 10 ** math.ceil(math.log10(0.7))
1
>>> 10 ** math.ceil(math.log10(1.1))
10
>>> 10 ** math.ceil(math.log10(90))
100
log10(n) gives you the solution x that satisfies 10 ** x == n, so if you round up x it gives you the exponent for the next highest power of 10.
Note that for a value n where x is already an integer, the "next highest power of 10" will be n:
>>> 10 ** math.ceil(math.log10(0.1))
0.1
>>> 10 ** math.ceil(math.log10(1))
1
>>> 10 ** math.ceil(math.log10(10))
10
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