MATLAB Unary Linear Regression Analysis

MATLAB unary linear regression analysis application example

Author: Kailugaji - Blog Park http://www.cnblogs.com/kailugaji/

huigui.m

function [b,bint,r,rint,states,sima2,p,y0,zxqj]= huigui(x,y,x0)
 %x – an n×p matrix of n observations of the independent variable of the p-element linear model, y - An n × 1 vector of n observations of the dependent variable of a p-element linear model, where x0 is the abscissa of the predicted value
%b - least squares estimate of model coefficient β, bint - 100(1-alpha)% confidence interval for model coefficient β, r - model fit residual, rint - 100(1-alpha) model fit residual )% confidence interval.
%stats - contains the R^2 statistic, the value of the F statistic of the ANOVA, the significant probability p value of the ANOVA and the estimated value of sigama^2, y0 is the predicted value ordinate 
format short ;
x1=[ones(length(x),1),x];
[b,bint,r,rint,states]=regress(y,x1);
sima2=(vpa(states(4),20));      
p =vpa(states( 3 ), 20 );    p value of % test p<0.01, the regression equation is highly significant; 0.0.1<=p<0.05, the regression equation is significant; p>=0.05 , the regression equation is not significant 
y0 = b( 1 )+b( 2 )* x0;
s=sqrt(states(4));
zxqj =[y0- 2 *s,y0+ 2 *s];    % confidence interval 
plot(x,y, ' . ' ),lsline
 %rcoplot(r,rint)    %residual analysis

result:

>> x=[1,2,3,4,5,6,7,8,9]';
>> y=[2,4,6,8,10,11,14,16,18]';
>> x0=10;
>> [b,bint,r,rint,states,sima2,p,y0,zxqj]=huigui(x,y,x0)

b =

   -0.0278
    1.9833

bint =

   -0.6342    0.5786
    1.8756    2.0911

r =

    0.0444
    0.0611
    0.0778
    0.0944
    0.1111
   -0.8722
    0.1444
    0.1611
    0.1778

rint =

   -0.6654    0.7543
   -0.7116    0.8338
   -0.7363    0.8918
   -0.7426    0.9315
   -0.7321    0.9543
   -0.8722   -0.8722
   -0.6611    0.9500
   -0.5981    0.9203
   -0.5124    0.8679

states =

   1.0e + 03 *

    0.0010    1.8941    0.0000    0.0001
 
sima2 =
 
0.12460317460317460317

p =
 
0.00000000088276169535500757861
 
y0 =

   19.8056

zxqj =

   19.0996   20.5115

Residual plot:

 

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