Title description
The difficulty of this question is not great, it is just a date conversion. I have done this question a long time ago.
1. First convert the entered date to the number of days from the beginning of the date: date = year 365+month 20+days
2. Find the year, month, and day of the Tzolkin calendar format according to date
year = date/260;
数字=date%13+1; (加1是因为数字从1开始)
天名字下标=date%20;（20个天名字的下标从0到19，根据计算出的天名字下标就可以得到相应的天名字）
#include <iostream>
#include <string>
using namespace std;
string Month[] = {
"pop", "no", "zip", "zotz", "tzec", "xul", "yoxkin", "mol", "chen", "yax", "zac", "ceh", "mac", "kankin", "muan", "pax", "koyab", "cumhu", "uayet" };
string Cycle[] = {
"imix", "ik", "akbal", "kan", "chicchan", "cimi", "manik", "lamat", "muluk", "ok", "chuen", "eb", "ben", "ix", "mem", "cib", "caban", "eznab", "canac", "ahau" };
int main(){
int n;
cin>>n;
float day;
string month;
int mm;
int year;
int date;
int i;
cout<<n<<endl;
while(n--){
cin>>day>>month>>year;
for(i=0;i<19;i++){
if(month==Month[i])
break;
}
date=365*year+20*i+day;
year=date/260;
mm=date%13+1;
day=date%20;
cout<<mm<<" "<<Cycle[(int)day]<<" "<<year<<endl;
}
}