C.63: Make move assignment non-virtual, take the parameter by &&, and return by non-const &
C.63:保证移动赋值运算符为非虚函数，参数类型为右值引用，返回值为常量引用类型
Reason（原因）
It is simple and efficient.
这样做简单且高效。
See（参见）:
The rule for copy-assignment.
拷贝赋值规则。
相关链接：
https://github.com/isocpp/CppCoreGuidelines/blob/master/CppCoreGuidelines.md#Rc-copy-assignment
Enforcement（实施建议）
Equivalent to what is done for copy-assignment.
和拷贝赋值的情况时所做的相同。
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(Simple) An assignment operator should not be virtual. Here be dragons!
（简单）赋值运算符不应该是虚函数。那样做很危险。
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(Simple) An assignment operator should return T& to enable chaining, not alternatives like const T& which interfere with composability and putting objects in containers.
（简单）赋值运算符应该返回T&，这样才能实现连续赋值。不要改成类似const T&的类型，这样会影响组装性并妨碍将对象放进容器中。
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(Moderate) A move assignment operator should (implicitly or explicitly) invoke all base and member move assignment operators.
（中等）移动赋值运算符应该（隐式或显式）调用所有的基类和成员的移动赋值运算符。
原文链接
https://github.com/isocpp/CppCoreGuidelines/blob/master/CppCoreGuidelines.md#c63-make-move-assignment-non-virtual-take-the-parameter-by--and-return-by-non-const-
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