java并发编程实战wwj----------第三阶段-------------ConcurrentHashMap----------------73

  红黑树的总结:https://www.jianshu.com/p/5dbaa6707017

  链表+数组+红黑树。

  首先看下node的数据结构:

static class Node<K,V> implements Map.Entry<K,V> {
        final int hash;
        final K key;
        volatile V val;
        volatile Node<K,V> next;

        Node(int hash, K key, V val, Node<K,V> next) {
            this.hash = hash;
            this.key = key;
            this.val = val;
            this.next = next;
        }

        public final K getKey()       { return key; }
        public final V getValue()     { return val; }
        public final int hashCode()   { return key.hashCode() ^ val.hashCode(); }
        public final String toString(){ return key + "=" + val; }
        public final V setValue(V value) {
            throw new UnsupportedOperationException();
        }

        public final boolean equals(Object o) {
            Object k, v, u; Map.Entry<?,?> e;
            return ((o instanceof Map.Entry) &&
                    (k = (e = (Map.Entry<?,?>)o).getKey()) != null &&
                    (v = e.getValue()) != null &&
                    (k == key || k.equals(key)) &&
                    (v == (u = val) || v.equals(u)));
        }

        /**
         * Virtualized support for map.get(); overridden in subclasses.
         */
        Node<K,V> find(int h, Object k) {
            Node<K,V> e = this;
            if (k != null) {
                do {
                    K ek;
                    if (e.hash == h &&
                        ((ek = e.key) == k || (ek != null && k.equals(ek))))
                        return e;
                } while ((e = e.next) != null);
            }
            return null;
        }
    }

TreeNode:

  static final class TreeNode<K,V> extends Node<K,V> {
        TreeNode<K,V> parent;  // red-black tree links
        TreeNode<K,V> left;
        TreeNode<K,V> right;
        TreeNode<K,V> prev;    // needed to unlink next upon deletion
        boolean red;

        TreeNode(int hash, K key, V val, Node<K,V> next,
                 TreeNode<K,V> parent) {
            super(hash, key, val, next);
            this.parent = parent;
        }

        Node<K,V> find(int h, Object k) {
            return findTreeNode(h, k, null);
        }

        /**
         * Returns the TreeNode (or null if not found) for the given key
         * starting at given root.
         */
        final TreeNode<K,V> findTreeNode(int h, Object k, Class<?> kc) {
            if (k != null) {
                TreeNode<K,V> p = this;
                do  {
                    int ph, dir; K pk; TreeNode<K,V> q;
                    TreeNode<K,V> pl = p.left, pr = p.right;
                    if ((ph = p.hash) > h)
                        p = pl;
                    else if (ph < h)
                        p = pr;
                    else if ((pk = p.key) == k || (pk != null && k.equals(pk)))
                        return p;
                    else if (pl == null)
                        p = pr;
                    else if (pr == null)
                        p = pl;
                    else if ((kc != null ||
                              (kc = comparableClassFor(k)) != null) &&
                             (dir = compareComparables(kc, k, pk)) != 0)
                        p = (dir < 0) ? pl : pr;
                    else if ((q = pr.findTreeNode(h, k, kc)) != null)
                        return q;
                    else
                        p = pl;
                } while (p != null);
            }
            return null;
        }
    }
TreeBin:红黑树的转换,锁的控制等。

知道这几个就开始看put的方法:

/** Implementation for put and putIfAbsent */
final V putVal(K key, V value, boolean onlyIfAbsent) {
    if (key == null || value == null) throw new NullPointerException();
    //1. 计算key的hash值
    int hash = spread(key.hashCode());
    int binCount = 0;
    for (Node<K,V>[] tab = table;;) {
        Node<K,V> f; int n, i, fh;
        //2. 如果当前table还没有初始化先调用initTable方法将tab进行初始化
        if (tab == null || (n = tab.length) == 0)
            tab = initTable();
        //3. tab中索引为i的位置的元素为null,则直接使用CAS将值插入即可
        else if ((f = tabAt(tab, i = (n - 1) & hash)) == null) {
            if (casTabAt(tab, i, null,
                         new Node<K,V>(hash, key, value, null)))
                break;                   // no lock when adding to empty bin
        }
        //4. 当前正在扩容
        else if ((fh = f.hash) == MOVED)
            tab = helpTransfer(tab, f);
        else {
            V oldVal = null;
            // 锁住红黑树的头部,红黑树的锁定只要锁头部即可
            synchronized (f) {
                if (tabAt(tab, i) == f) {
                    //5. 当前为链表,在链表中插入新的键值对
                    if (fh >= 0) {
                        binCount = 1;
                        for (Node<K,V> e = f;; ++binCount) {
                            K ek;
                            if (e.hash == hash &&
                                ((ek = e.key) == key ||
                                 (ek != null && key.equals(ek)))) {
                                oldVal = e.val;
                                if (!onlyIfAbsent)
                                    e.val = value;
                                break;
                            }
                            Node<K,V> pred = e;
                            if ((e = e.next) == null) {
                                pred.next = new Node<K,V>(hash, key,
                                                          value, null);
                                break;
                            }
                        }
                    }
                    // 6.当前为红黑树,将新的键值对插入到红黑树中
                    else if (f instanceof TreeBin) {
                        Node<K,V> p;
                        binCount = 2;
                        if ((p = ((TreeBin<K,V>)f).putTreeVal(hash, key,
                                                       value)) != null) {
                            oldVal = p.val;
                            if (!onlyIfAbsent)
                                p.val = value;
                        }
                    }
                }
            }
            // 7.插入完键值对后再根据实际大小看是否需要转换成红黑树
            if (binCount != 0) {
                if (binCount >= TREEIFY_THRESHOLD)
                    treeifyBin(tab, i);
                if (oldVal != null)
                    return oldVal;
                break;
            }
        }
    }
    //8.对当前容量大小进行检查,如果超过了临界值(实际大小*加载因子)就需要扩容 
    addCount(1L, binCount);
    return null;
}

扩容:https://blog.csdn.net/varyall/article/details/81277296

get:

public V get(Object key) {
    Node<K,V>[] tab; Node<K,V> e, p; int n, eh; K ek;
    int h = spread(key.hashCode()); //计算两次hash
    if ((tab = table) != null && (n = tab.length) > 0 &&
        (e = tabAt(tab, (n - 1) & h)) != null) {//读取首节点的Node元素
        if ((eh = e.hash) == h) { //如果该节点就是首节点就返回
            if ((ek = e.key) == key || (ek != null && key.equals(ek)))
                return e.val;
        }
        //hash值为负值表示正在扩容,这个时候查的是ForwardingNode的find方法来定位到nextTable来
        //查找,查找到就返回
        else if (eh < 0)
            return (p = e.find(h, key)) != null ? p.val : null;
        while ((e = e.next) != null) {//既不是首节点也不是ForwardingNode,那就往下遍历
            if (e.hash == h &&
                ((ek = e.key) == key || (ek != null && key.equals(ek))))
                return e.val;
        }
    }
    return null;
}
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