winform中如何选中datagridview中的一行数据双击后跳转并将其显示在另一个页面的datagirdview中

Form1：

    public  static  string [] a;

   private  void  dataGridView1_DoubleClick( object  sender, EventArgs e) //添加datagridview1的双击事件

         {

             try

             {

                 int  index = dataGridView1.CurrentRow.Index;

                 a =  new  string [dataGridView1.ColumnCount];

                 for  ( int  i = 0; i < dataGridView1.ColumnCount; i++)

                 {

                     a[i] = dataGridView1.Rows[index].Cells[i].Value.ToString();

                  }

                 Form2 f2 =  new  Form2();

                 f2.Show();

                                                                       

             }

             catch  { }

         }

Form2: //

   public  Form2()

         {

             InitializeComponent();

             showGridView();

         }

   private  void  showGridView()

         {

             DataGridTextBoxColumn tb =  new  DataGridTextBoxColumn();

             dataGridView1.Rows.Add(tb);

             for  ( int  i = 0; i < dataGridView1.ColumnCount;i++ )

                 dataGridView1.Rows[dataGridView1.RowCount-2].Cells[i].Value = Form1.a[i]; //根据AllowUserToAddRow属性选择最后一行，true时dataGridView1.RowCount-2,false时dataGridView1.RowCount-1

         }